Обсуждение: Replacing Ordinal Suffixes

Try this:

SELECT REGEXP_REPLACE(LOWER('300 North 126th Street'),
'(\d)(st|nd|rd|th)', '\1', 'g');

Note that matching a number is \d not /D: backslash, not forward
slash, and lowercase d not uppercase. \d means a digit, \D means
anything except a digit.

Also, I don't think Postgres supports positive lookbehind expressions
(which are actually (?<=foo), not (?!foo)), but you can get the same
effect by capturing the number with (\d) and then outputting it again
with the \1.

Paul



On Fri, Feb 28, 2014 at 2:04 PM, George Weaver <gweaver@shaw.ca> wrote:
> Hi list,
>
> I'm stumped.
>
> I am trying to use Regexp_Replace to replace ordinal suffixes in addresses
> (eg have '126th' want '126') for comparison purposes.  So far no luck.
>
> I have found that
>
> SELECT REGEXP_REPLACE(LOWER('300 North 126th Street'),
> '(?!/D)(st|nd|rd|th)', '', 'g');
>   regexp_replace
> ------------------
>  300 nor 126 reet
>
> but
>
> SELECT REGEXP_REPLACE(LOWER('300 North 126th Street'),
> '(?=/D)(st|nd|rd|th)', '', 'g');
>      regexp_replace
> ------------------------
>  300 north 126th street
>
> I'm a novice with regular expressions and google hasn't helped much.
>
> Any suggestions?
>
> Thanks,
> George



--
_________________________________
Pulchritudo splendor veritatis.

On Feb 28, 2014, at 2:04 PM, George Weaver <gweaver@shaw.ca> wrote:

> Hi list,
>
> I'm stumped.
>
> I am trying to use Regexp_Replace to replace ordinal suffixes in addresses (eg have '126th' want '126') for
comparisonpurposes.  So far no luck. 
>
> I have found that
>
> SELECT REGEXP_REPLACE(LOWER('300 North 126th Street'), '(?!/D)(st|nd|rd|th)', '', 'g');
>   regexp_replace
> ------------------
>  300 nor 126 reet
>
> but
>
> SELECT REGEXP_REPLACE(LOWER('300 North 126th Street'), '(?=/D)(st|nd|rd|th)', '', 'g');
>      regexp_replace
> ------------------------
>  300 north 126th street
>
> I'm a novice with regular expressions and google hasn't helped much.
>
> Any suggestions?

Maybe this?

select regexp_replace('300 North 126th Street', '(\d+)(?:st|nd|rd|th)', '\1', 'gi');

Cheers,
  Steve

This is a kick *ss forum. I must say.


On Fri, 2014-02-28 at 14:17 -0800, Steve Atkins wrote:
> On Feb 28, 2014, at 2:04 PM, George Weaver <gweaver@shaw.ca> wrote:
>
> > Hi list,
> >
> > I'm stumped.
> >
> > I am trying to use Regexp_Replace to replace ordinal suffixes in addresses (eg have '126th' want '126') for
comparisonpurposes.  So far no luck. 
> >
> > I have found that
> >
> > SELECT REGEXP_REPLACE(LOWER('300 North 126th Street'), '(?!/D)(st|nd|rd|th)', '', 'g');
> >   regexp_replace
> > ------------------
> >  300 nor 126 reet
> >
> > but
> >
> > SELECT REGEXP_REPLACE(LOWER('300 North 126th Street'), '(?=/D)(st|nd|rd|th)', '', 'g');
> >      regexp_replace
> > ------------------------
> >  300 north 126th street
> >
> > I'm a novice with regular expressions and google hasn't helped much.
> >
> > Any suggestions?
>
> Maybe this?
>
> select regexp_replace('300 North 126th Street', '(\d+)(?:st|nd|rd|th)', '\1', 'gi');
>
> Cheers,
>   Steve
>
>
>

From: Paul Jungwirth

>Try this:

>SELECT REGEXP_REPLACE(LOWER('300 North 126th Street'),
'(\d)(st|nd|rd|th)', '\1', 'g');

Hi Paul,

No luck...

SELECT REGEXP_REPLACE(LOWER('300 North 126th Street'), E'(\d)(st|nd|rd|th)',
E'\1', 'g');
     regexp_replace
------------------------
 300 north 126th street
(1 row)

>Note that matching a number is \d not /D: backslash, not forward
>slash, and lowercase d not uppercase. \d means a digit, \D means
>anything except a digit.

>Also, I don't think Postgres supports positive lookbehind expressions
>(which are actually (?<=foo), not (?!foo)), but you can get the same
>effect by capturing the number with (\d) and then outputting it again
>with the \1.

>Paul



On Fri, Feb 28, 2014 at 2:04 PM, George Weaver <gweaver@shaw.ca> wrote:
> Hi list,
>
> I'm stumped.
>
> I am trying to use Regexp_Replace to replace ordinal suffixes in addresses
> (eg have '126th' want '126') for comparison purposes.  So far no luck.
>
> I have found that
>
> SELECT REGEXP_REPLACE(LOWER('300 North 126th Street'),
> '(?!/D)(st|nd|rd|th)', '', 'g');
>   regexp_replace
> ------------------
>  300 nor 126 reet
>
> but
>
> SELECT REGEXP_REPLACE(LOWER('300 North 126th Street'),
> '(?=/D)(st|nd|rd|th)', '', 'g');
>      regexp_replace
> ------------------------
>  300 north 126th street
>
> I'm a novice with regular expressions and google hasn't helped much.
>
> Any suggestions?
>
> Thanks,
> George



--
_________________________________
Pulchritudo splendor veritatis.

From: Steve Atkins

On Feb 28, 2014, at 2:04 PM, George Weaver <gweaver@shaw.ca> wrote:

> Hi list,
>
> I'm stumped.
>
> I am trying to use Regexp_Replace to replace ordinal suffixes in addresses
> (eg have '126th' want '126') for comparison purposes.  So far no luck.
>
> I have found that
>
> SELECT REGEXP_REPLACE(LOWER('300 North 126th Street'),
> '(?!/D)(st|nd|rd|th)', '', 'g');
>   regexp_replace
> ------------------
>  300 nor 126 reet
>
> but
>
> SELECT REGEXP_REPLACE(LOWER('300 North 126th Street'),
> '(?=/D)(st|nd|rd|th)', '', 'g');
>      regexp_replace
> ------------------------
>  300 north 126th street
>
> I'm a novice with regular expressions and google hasn't helped much.
>
> Any suggestions?

>Maybe this?

>select regexp_replace('300 North 126th Street', '(\d+)(?:st|nd|rd|th)',
>'\1', 'gi');

Hi Steve,

Thanks, but no luck:

select regexp_replace('300 North 126th Street', E'(\d+)(?:st|nd|rd|th)',
E'\1', 'gi');
     regexp_replace
------------------------
 300 North 126th Street

George

Cheers,
  Steve




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On Feb 28, 2014, at 2:43 PM, George Weaver <gweaver@shaw.ca> wrote:

> From: Steve Atkins
>
> >Maybe this?
>
> >select regexp_replace('300 North 126th Street', '(\d+)(?:st|nd|rd|th)',
> >'\1', 'gi');
>
> Hi Steve,
>
> Thanks, but no luck:
>
> select regexp_replace('300 North 126th Street', E'(\d+)(?:st|nd|rd|th)',
> E'\1', 'gi');
>      regexp_replace
> ------------------------
>  300 North 126th Street
>
> George

Those E’s you added completely change the meaning. If you want to
use E-style literals (and you probably don’t) you’ll need to double the
backslashes in all the strings.

Cheers,
  Steve

>----- Original Message -----
>From: Steve Atkins

>On Feb 28, 2014, at 2:43 PM, George Weaver <gweaver@shaw.ca> wrote:
>
> >Maybe this?
>
> >select regexp_replace('300 North 126th Street', '(\d+)(?:st|nd|rd|th)',
> >'\1', 'gi');
>
> Hi Steve,
>
> Thanks, but no luck:
>
> select regexp_replace('300 North 126th Street', E'(\d+)(?:st|nd|rd|th)',
> E'\1', 'gi');
>      regexp_replace
> ------------------------
>  300 North 126th Street
>
> George

>Those E’s you added completely change the meaning. If you want to
>use E-style literals (and you probably don’t) you’ll need to double the
>backslashes in all the strings.

Hi Steve,

Without the E's:

development=# select regexp_replace('300 North 126th Street',
'(\d+)(?:st|nd|rd|th)', '\1', 'gi');
WARNING:  nonstandard use of escape in a string literal
LINE 1: select regexp_replace('300 North 126th Street', '(\d+)(?:st|...
                                                        ^
HINT:  Use the escape string syntax for escapes, e.g., E'\r\n'.
WARNING:  nonstandard use of escape in a string literal
LINE 1: ...'300 North 126th Street', '(\d+)(?:st|nd|rd|th)', '\1', 'gi'...
                                                             ^
HINT:  Use the escape string syntax for escapes, e.g., E'\r\n'.
     regexp_replace
------------------------
 300 North 126th Street
(1 row)

Frustrating...

>Cheers,
 > Steve



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----- Original Message -----
From: Steve Atkins
To: pgsql-general
Sent: Friday, February 28, 2014 4:17 PM
Subject: Re: [GENERAL] Replacing Ordinal Suffixes



On Feb 28, 2014, at 2:04 PM, George Weaver <gweaver@shaw.ca> wrote:

> Hi list,
>
> I'm stumped.
>
> I am trying to use Regexp_Replace to replace ordinal suffixes in addresses
> (eg have '126th' want '126') for comparison purposes.  So far no luck.
>
> I have found that
>
> SELECT REGEXP_REPLACE(LOWER('300 North 126th Street'),
> '(?!/D)(st|nd|rd|th)', '', 'g');
>   regexp_replace
> ------------------
>  300 nor 126 reet
>
> but
>
> SELECT REGEXP_REPLACE(LOWER('300 North 126th Street'),
> '(?=/D)(st|nd|rd|th)', '', 'g');
>      regexp_replace
> ------------------------
>  300 north 126th street
>
> I'm a novice with regular expressions and google hasn't helped much.
>
> Any suggestions?

>Maybe this?

>select regexp_replace('300 North 126th Street', '(\d+)(?:st|nd|rd|th)',
>'\1', 'gi');

Hi Steve,

Thanks, but no luck:

select regexp_replace('300 North 126th Street', E'(\d+)(?:st|nd|rd|th)',
E'\1', 'gi');
     regexp_replace
------------------------
 300 North 126th Street

George

Cheers,
  Steve




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2014-03-01 8:16 GMT+09:00 George Weaver <gweaver@shaw.ca>:
>
>> ----- Original Message ----- From: Steve Atkins
>
>
>> On Feb 28, 2014, at 2:43 PM, George Weaver <gweaver@shaw.ca> wrote:
>>
>> >Maybe this?
>>
>> >select regexp_replace('300 North 126th Street', '(\d+)(?:st|nd|rd|th)',
>> >'\1', 'gi');
>>
>> Hi Steve,
>>
>> Thanks, but no luck:
>>
>> select regexp_replace('300 North 126th Street', E'(\d+)(?:st|nd|rd|th)',
>> E'\1', 'gi');
>>      regexp_replace
>> ------------------------
>>  300 North 126th Street
>>
>> George
>
>
>> Those E’s you added completely change the meaning. If you want to
>> use E-style literals (and you probably don’t) you’ll need to double the
>> backslashes in all the strings.
>
>
> Hi Steve,
>
> Without the E's:
>
> development=# select regexp_replace('300 North 126th Street',
> '(\d+)(?:st|nd|rd|th)', '\1', 'gi');
> WARNING:  nonstandard use of escape in a string literal
> LINE 1: select regexp_replace('300 North 126th Street', '(\d+)(?:st|...
>                                                        ^
> HINT:  Use the escape string syntax for escapes, e.g., E'\r\n'.
> WARNING:  nonstandard use of escape in a string literal
> LINE 1: ...'300 North 126th Street', '(\d+)(?:st|nd|rd|th)', '\1', 'gi'...
>                                                             ^
> HINT:  Use the escape string syntax for escapes, e.g., E'\r\n'.
>
>     regexp_replace
> ------------------------
> 300 North 126th Street
> (1 row)
>
> Frustrating...

Per Steve Atkin's note about double backslashes:

    postgres=> select regexp_replace('300 North 126th Street',
E'(\\d+)(?:st|nd|rd|th)', E'\\1', 'gi');
        regexp_replace
    ----------------------
     300 North 126 Street
    (1 row)

Regards

Ian Barwick

From: Ian Lawrence Barwick
>
>> ----- Original Message ----- From: Steve Atkins
>
>
>> On Feb 28, 2014, at 2:43 PM, George Weaver <gweaver@shaw.ca> wrote:
>>
>> >Maybe this?
>>
>> >select regexp_replace('300 North 126th Street', '(\d+)(?:st|nd|rd|th)',
>> >'\1', 'gi');
>>
>> Hi Steve,
>>
>> Thanks, but no luck:
>>
>> select regexp_replace('300 North 126th Street', E'(\d+)(?:st|nd|rd|th)',
>> E'\1', 'gi');
>>      regexp_replace
>> ------------------------
>>  300 North 126th Street
>>
>> George
>
>
>> Those E’s you added completely change the meaning. If you want to
>> use E-style literals (and you probably don’t) you’ll need to double the
>> backslashes in all the strings.
>
>
> Hi Steve,
>
> Without the E's:
>
> development=# select regexp_replace('300 North 126th Street',
> '(\d+)(?:st|nd|rd|th)', '\1', 'gi');
> WARNING:  nonstandard use of escape in a string literal
> LINE 1: select regexp_replace('300 North 126th Street', '(\d+)(?:st|...
>                                                        ^
> HINT:  Use the escape string syntax for escapes, e.g., E'\r\n'.
> WARNING:  nonstandard use of escape in a string literal
> LINE 1: ...'300 North 126th Street', '(\d+)(?:st|nd|rd|th)', '\1', 'gi'...
>                                                             ^
> HINT:  Use the escape string syntax for escapes, e.g., E'\r\n'.
>
>     regexp_replace
> ------------------------
> 300 North 126th Street
> (1 row)
>
> Frustrating...

Per Steve Atkin's note about double backslashes:

    postgres=> select regexp_replace('300 North 126th Street',
E'(\\d+)(?:st|nd|rd|th)', E'\\1', 'gi');
        regexp_replace
    ----------------------
     300 North 126 Street
    (1 row)

Hi Ian,

I just got that as well - awesome!

Regards

Ian Barwick

>>>>> "GW" == George Weaver <gweaver@shaw.ca> writes:

GW> SELECT REGEXP_REPLACE(LOWER('300 North 126th Street'),
GW> E'(\d)(st|nd|rd|th)', E'\1', 'g');
GW>     regexp_replace
GW> ------------------------
GW> 300 north 126th street
GW> (1 row)

The E'' syntax eats your backslashes.  For that version, try just:

SELECT REGEXP_REPLACE(LOWER('300 North 126th Street'),'(\d)(st|nd|rd|th)', '\1', 'g');

-JimC
--
James Cloos <cloos@jhcloos.com>         OpenPGP: 1024D/ED7DAEA6

George Weaver wrote:

> Hi Ian,
>
> I just got that as well - awesome!

http://xkcd.com/1313/

--
Álvaro Herrera                http://www.2ndQuadrant.com/
PostgreSQL Development, 24x7 Support, Training & Services

Hi All,

>From: James Cloos

>The E'' syntax eats your backslashes.  For that version, try just:

>SELECT REGEXP_REPLACE(LOWER('300 North 126th Street'),'(\d)(st|nd|rd|th)',
>'\1', 'g');

Actually, I found that the double backslashes are required whether the E is
used or not:

development=# select regexp_replace('300 North 126th Street',
'(\d+)(?:st|nd|rd|th)', '\1', 'gi');
WARNING:  nonstandard use of escape in a string literal
LINE 1: select regexp_replace('300 North 126th Street', '(\d+)(?:st|...
                                                        ^
HINT:  Use the escape string syntax for escapes, e.g., E'\r\n'.
WARNING:  nonstandard use of escape in a string literal
LINE 1: ...'300 North 126th Street', '(\d+)(?:st|nd|rd|th)', '\1', 'gi'...
                                                             ^
HINT:  Use the escape string syntax for escapes, e.g., E'\r\n'.
     regexp_replace
------------------------
 300 North 126th Street
(1 row)

development=# select regexp_replace('300 North 126th Street',
'(\\d+)(?:st|nd|rd|th)', '\\1', 'gi');
WARNING:  nonstandard use of \\ in a string literal
LINE 1: select regexp_replace('300 North 126th Street', '(\\d+)(?:st...
                                                        ^
HINT:  Use the escape string syntax for backslashes, e.g., E'\\'.
WARNING:  nonstandard use of \\ in a string literal
LINE 1: ...300 North 126th Street', '(\\d+)(?:st|nd|rd|th)', '\\1', 'gi...
                                                             ^
HINT:  Use the escape string syntax for backslashes, e.g., E'\\'.
    regexp_replace
----------------------
 300 North 126 Street
(1 row)

development=# select regexp_replace('300 North 126th Street',
E'(\\d+)(?:st|nd|rd|th)', E'\\1', 'gi');
    regexp_replace
----------------------
 300 North 126 Street

I appreciate the help of everyone who responded!

Cheers,
George

"George Weaver" <gweaver@shaw.ca> writes:
> Actually, I found that the double backslashes are required whether the E is
> used or not:

You must be using a relatively old PG version then.  Default behavior
since around 9.1 has been that backslashes aren't special except
in E'' strings.

            regards, tom lane

> Actually, I found that the double backslashes are required whether the E
> is
> used or not:

>You must be using a relatively old PG version then.  Default behavior
>since around 9.1 has been that backslashes aren't special except
>in E'' strings.

Hmm.

development=# select version();
                           version
------------------------------------------------------------
 PostgreSQL 9.1.9, compiled by Visual C++ build 1500, 32-bit
(1 row)

>regards, tom lane

On Mar 1, 2014, at 11:45 AM, George Weaver <gweaver@shaw.ca> wrote:

>
>> Actually, I found that the double backslashes are required whether the E is
>> used or not:
>
>> You must be using a relatively old PG version then.  Default behavior
>> since around 9.1 has been that backslashes aren't special except
>> in E'' strings.
>
> Hmm.
>
> development=# select version();
>                          version
> ------------------------------------------------------------
> PostgreSQL 9.1.9, compiled by Visual C++ build 1500, 32-bit
> (1 row)

steve=# select version();
                                                                                 version

--------------------------------------------------------------------------------------------------------------------------------------------------------------------------
 PostgreSQL 9.1.4 on x86_64-apple-darwin12.0.0, compiled by i686-apple-darwin11-llvm-gcc-4.2 (GCC) 4.2.1 (Based on
AppleInc. build 5658) (LLVM build 2336.11.00), 64-bit 
(1 row)

steve=# select regexp_replace('300 North 126th Street', '(\d+)(?:st|nd|rd|th)', '\1', 'gi');
    regexp_replace
----------------------
 300 North 126 Street
(1 row)


I suspect you have standard_conforming_strings set to off (it defaults to on in 9.1), possibly for backwards
compatibilityto support an app you’re using that’s not been updated, possibly accidentally. 

Cheers,
  Steve

----- Original Message -----
From: Steve Atkins

<snip>

>I suspect you have standard_conforming_strings set to off (it defaults to
>on in 9.1), possibly for backwards compatibility to support an app you’re
>using that’s not been updated, possibly accidentally.

You're right - it was off (now On).  Though for the life of me I can't say
why...

On the production installations I support its On.

Thanks!

>Cheers,
 > Steve