From: Paul Jungwirth
>Try this:
>SELECT REGEXP_REPLACE(LOWER('300 North 126th Street'),
'(\d)(st|nd|rd|th)', '\1', 'g');
Hi Paul,
No luck...
SELECT REGEXP_REPLACE(LOWER('300 North 126th Street'), E'(\d)(st|nd|rd|th)',
E'\1', 'g');
regexp_replace
------------------------
300 north 126th street
(1 row)
>Note that matching a number is \d not /D: backslash, not forward
>slash, and lowercase d not uppercase. \d means a digit, \D means
>anything except a digit.
>Also, I don't think Postgres supports positive lookbehind expressions
>(which are actually (?<=foo), not (?!foo)), but you can get the same
>effect by capturing the number with (\d) and then outputting it again
>with the \1.
>Paul
On Fri, Feb 28, 2014 at 2:04 PM, George Weaver <gweaver@shaw.ca> wrote:
> Hi list,
>
> I'm stumped.
>
> I am trying to use Regexp_Replace to replace ordinal suffixes in addresses
> (eg have '126th' want '126') for comparison purposes. So far no luck.
>
> I have found that
>
> SELECT REGEXP_REPLACE(LOWER('300 North 126th Street'),
> '(?!/D)(st|nd|rd|th)', '', 'g');
> regexp_replace
> ------------------
> 300 nor 126 reet
>
> but
>
> SELECT REGEXP_REPLACE(LOWER('300 North 126th Street'),
> '(?=/D)(st|nd|rd|th)', '', 'g');
> regexp_replace
> ------------------------
> 300 north 126th street
>
> I'm a novice with regular expressions and google hasn't helped much.
>
> Any suggestions?
>
> Thanks,
> George
--
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