Re: Update with last known location?

On 28 January 2014 23:15, Gavin Flower <GavinFlower@archidevsys.co.nz> wrote:
> On 29/01/14 11:00, Kevin Grittner wrote:
>>
>> James David Smith <james.david.smith@gmail.com> wrote:
>>
>>> Given the data is so large I don't want to be taking the data out
>>> to a CSV or whatever and then loading it back in. I'd like to do
>>> this within the database using SQL. I thought I would be able to
>>> do this using a LOOP to be honest.
>>
>> I would be amazed if you couldn't do this with  a single UPDATE
>> statement.  I've generally found declarative forms of such work to
>> be at least one order of magnitude faster than going to either a PL
>> or a script approach.  I would start by putting together a SELECT
>> query using window functions and maybe a CTE or two to list all the
>> primary keys which need updating and the new values they should
>> have.  Once that SELECT was looking good, I would put it in the
>> FROM clause of an UPDATE statement.
>>
>> That should work, but if you are updating a large percentage of the
>> table, I would go one step further before running this against the
>> production tables.  I would put a LIMIT on the above-mentioned
>> SELECT of something like 10000 rows, and script a loop that
>> alternates between the UPDATE and a VACUUM ANALYZE on the table.
>>
>> --
>> Kevin Grittner
>> EDB: http://www.enterprisedb.com
>> The Enterprise PostgreSQL Company
>>
>>
> James, you might consider dropping as many indexes on the table as you
> safely can, and rebuilding them after the mass update.  If you have lots of
> such indexes, you will find this apprtoach to be a lot faster.
>
>
> Cheers,
> Gavin

Hi all,

Thanks for your help and assistance. I think that window functions,
and inparticular the PARTITION function, is 100% the way to go.  I've
been concentrating on a SELECT statement for now and am close but not
quite close enough. The below query gets all the data I want, but
*too* much. What I've essentially done is:

- Select all the rows that don't have any geom information
- Join them with all rows before this point that *do* have geom information.
- Before doing this join, use partition to generate row numbers.

The attached screen grab shows the result of my query below.
Unfortunately this is generating alot of joins that I don't want. This
won't be practical when doing it with 75,000 people.

Thoughts and code suggestions very much appreciated... if needed I
could put together some SQL to create an example table?

Thanks

SELECT     row_number() OVER (PARTITION BY test.point_time ORDER BY
test.point_time) as test_row,
    test.ppid as test_ppid,
    test.point_time as test_point_time,
    test.the_geom as test_the_geom,
    a.ppid as a_ppid,
    a.point_time as a_point_time,
    a.the_geom as a_the_geom,
    a.a_row
FROM     test
    LEFT JOIN (
        SELECT    the_geom,
            ppid,
            point_time,
            row_number() OVER (ORDER BY ppid, point_time) as a_row
        FROM     test
        WHERE     the_geom IS NOT NULL) a
ON    a.point_time < test.point_time
AND    a.ppid = test.ppid
WHERE    test.the_geom IS NULL
ORDER BY test.point_time)


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