Re: Query with Parameters and Wildcards
От | dayat |
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Тема | Re: Query with Parameters and Wildcards |
Дата | |
Msg-id | 487E9B6FF30F43DFB2DC0B00E81DAF7A@dayatPC обсуждение исходный текст |
Ответ на | Re: Query with Parameters and Wildcards (landsharkdaddy <ldodd@landsharksoftware.com>) |
Ответы |
Re: Query with Parameters and Wildcards
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Список | pgsql-sql |
Do you run this code in the function? If so, the following example function with LANGUAGE SQL function: CREATE OR REPLACE FUNCTION TEST(lastnameVARCHAR) RETURNS SETOF lanemanager.customers AS $$ SELECT customercellphone, customercity, customerdatecreated, customerdatelastmodified, customeremail, customerfax, customerfirstname, customerid, customerlastname, customermiddleinitial, customerphone, customerreferredby, customerstateabbr, customerstreet1, customerstreet2, customersuffix, customertitle, customerworkphone, customerworkphoneext, customerzip FROM lanemanager.customers WHERE (customerlastname ILIKE $1 || '%') $$ LANGUAGE SQL; Please tell me is it work for you. Regards Hidayat ----- Original Message ----- From: "landsharkdaddy" <ldodd@landsharksoftware.com> To: <pgsql-sql@postgresql.org> Sent: Monday, April 27, 2009 9:19 PM Subject: Re: [SQL] Query with Parameters and Wildcards > > When I try the following like you suggested I get an error that says > "operator does not exist: || unknown > > > > SELECT customercellphone, customercity, customerdatecreated, > customerdatelastmodified, customeremail, customerfax, customerfirstname, > customerid, customerlastname, customermiddleinitial, customerphone, > customerreferredby, customerstateabbr, customerstreet1, customerstreet2, > customersuffix, customertitle, customerworkphone, customerworkphoneext, > customerzip FROM lanemanager.customers WHERE (customerlastname ILIKE || > '%') > > > > > > landsharkdaddy wrote: >> >> I have a query that works on SQL Server to return customers that contain >> the string entered by the user by accepting parameters and using the LIKE >> keyword. I would like to move this to postgreSQL but I'm just not sure >> how >> to get it done. This is the query >> >> SELECT * FROM Customers WHERE FirstName LIKE @custfirst + '%'; >> >> This works great on SQL Server but not on postgreSQL. Any help would be >> appreciated. __________________________________________________ Apakah Anda Yahoo!? Lelah menerima spam? Surat Yahoo! memiliki perlindungan terbaik terhadap spam http://id.mail.yahoo.com
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