Обсуждение: [GENERAL] Issue with json_agg() and ordering

Поиск
Список
Период
Сортировка

[GENERAL] Issue with json_agg() and ordering

От
Bob Jones
Дата:
Hi,


Could anyone give me a few pointers as to how I might resolve the following :

select json_agg(my_table) from (my_table) where foo='test' and bar='f'
order by last_name asc, first_name asc;

ERROR:  column "my_table.last_name" must appear in the GROUP BY clause
or be used in an aggregate function
LINE 1: ...foo='f' order by last_name ...


I suspect It doesn't really matter what my table looks like for the
purposes of the above, but if you need something to go by:

create table my_table(
last_name text,
first name text,
foo text,
bar boolean
);

Thanks !

Bob


Re: [GENERAL] Issue with json_agg() and ordering

От
"Charles Clavadetscher"
Дата:
Hello

> -----Original Message-----
> From: pgsql-general-owner@postgresql.org [mailto:pgsql-general-owner@postgresql.org] On Behalf Of Bob Jones
> Sent: Freitag, 1. September 2017 10:12
> To: pgsql-general <pgsql-general@postgresql.org>
> Subject: [GENERAL] Issue with json_agg() and ordering
>
> Hi,
>
>
> Could anyone give me a few pointers as to how I might resolve the following :
>
> select json_agg(my_table) from (my_table) where foo='test' and bar='f'
> order by last_name asc, first_name asc;
>
> ERROR:  column "my_table.last_name" must appear in the GROUP BY clause or be used in an aggregate function LINE 1:
> ...foo='f' order by last_name ...

I guess that the order by should be in the aggregation.

SELECT json_agg(a.* ORDER BY a.last_name, a.last_year DESC)
FROM my_table a;

Regards
Charles

>
>
> I suspect It doesn't really matter what my table looks like for the purposes of the above, but if you need something
> to go by:
>
> create table my_table(
> last_name text,
> first name text,
> foo text,
> bar boolean
> );
>
> Thanks !
>
> Bob
>
>
> --
> Sent via pgsql-general mailing list (pgsql-general@postgresql.org) To make changes to your subscription:
> http://www.postgresql.org/mailpref/pgsql-general



Re: [GENERAL] Issue with json_agg() and ordering

От
Merlin Moncure
Дата:
On Fri, Sep 1, 2017 at 6:22 AM, Charles Clavadetscher
<clavadetscher@swisspug.org> wrote:
> Hello
>
>> -----Original Message-----
>> From: pgsql-general-owner@postgresql.org [mailto:pgsql-general-owner@postgresql.org] On Behalf Of Bob Jones
>> Sent: Freitag, 1. September 2017 10:12
>> To: pgsql-general <pgsql-general@postgresql.org>
>> Subject: [GENERAL] Issue with json_agg() and ordering
>>
>> Hi,
>>
>>
>> Could anyone give me a few pointers as to how I might resolve the following :
>>
>> select json_agg(my_table) from (my_table) where foo='test' and bar='f'
>> order by last_name asc, first_name asc;
>>
>> ERROR:  column "my_table.last_name" must appear in the GROUP BY clause or be used in an aggregate function LINE 1:
>> ...foo='f' order by last_name ...
>
> I guess that the order by should be in the aggregation.
>
> SELECT json_agg(a.* ORDER BY a.last_name, a.last_year DESC)
> FROM my_table a;

yes.  however, you would say, json_agg(a... not 'a.*').  The .*
notation only works in certain contexts, and is transformed at parse
time to, a.col1, a.col2, a.col3...  which would not work inside an
aggregation function which can only handle a single column or record.

merlin


Re: [GENERAL] Issue with json_agg() and ordering

От
Bob Jones
Дата:
>>
>> I guess that the order by should be in the aggregation.
>>
>> SELECT json_agg(a.* ORDER BY a.last_name, a.last_year DESC)
>> FROM my_table a;
>
> yes.  however, you would say, json_agg(a... not 'a.*').  The .*
> notation only works in certain contexts, and is transformed at parse
> time to, a.col1, a.col2, a.col3...  which would not work inside an
> aggregation function which can only handle a single column or record.
>
> merlin


Awesome ! Thanks Charles for the answer, and Merlin for the
tweaking/additional insight.