Обсуждение: sql
Hi All<br /><br /> this is my table ;<br />| ID |entry_user_id_int | category_id_chv |<br />----------------------------------------------<br/>| 1 | 78 | CV |<br />----------------------------------------------<br />| 2 | 78 | VC |<br />----------------------------------------------<br/>| 3 | 78 | CV |<br />----------------------------------------------<br/> | 4 | 78 | CV |<br />----------------------------------------------<br/>| 5 | 78 | CV |<br />----------------------------------------------<br/>| 6 | 78 | CV | <br />----------------------------------------------<br/>| 7 | 78 | CV |<br />----------------------------------------------<br/>| 8 | 78 | CV |<br />----------------------------------------------<br />| 9 | 78 | VE |<br />----------------------------------------------<br/>| 10 | 78 | CV |<br />----------------------------------------------<br/>| 11 | 78 | SC | <br />----------------------------------------------<br/><br />WHEN "select entry_user_id_int, category_id_chv,count(category_id_chv)from vigilance_master group by category_id_chv,entry_user_id_int having" entry_user_id_int=78<br />result is :<br /><br />ID entry_user_id_int category_id_chv count <br /><br />1 78 VC 1<br />2 78 VE 1<br />3 78 CV 8 <br />4 78 SC 1<br /><br />BUT I NEED THE RESULT AS <br />entry_user_id_int COUNT(VC) COUNT(VE) COUNT(CV) COUNT(SC) TOTAL<br /> 78 1 1 8 1 11<br /><br /><br /><br /><br />
am Fri, dem 02.02.2007, um 13:09:09 +0530 mailte Shyju Narayanan folgendes: > Hi All > > > BUT I NEED THE RESULT AS > entry_user_id_int COUNT(VC) COUNT(VE) COUNT(CV) COUNT(SC) TOTAL > 78 1 1 8 1 11 > You need something like this (i called the table foo and without the sc-column): select entry_user_id_int, sum(case when category_id_chv = 'VC' then 1 else 0 end) as "count(vc)", sum(case when category_id_chv= 'VE' then 1 else 0 end), sum(case when category_id_chv = 'CV' then 1 else 0 end), sum(1) from foo where entry_user_id_int = 78 group by entry_user_id_int;entry_user_id_int | count(vc) | sum | sum | sum -------------------+-----------+-----+-----+----- 78 | 1 | 1 | 8 | 11 Andreas -- Andreas Kretschmer Kontakt: Heynitz: 035242/47150, D1: 0160/7141639 (mehr: -> Header) GnuPG-ID: 0x3FFF606C, privat 0x7F4584DA http://wwwkeys.de.pgp.net
try this:
select entry_user_id, sum(decode(entry_user_id,'VC',1,0) as vc, sum(decode(entry_user_id,'VE',1,0) as ve,
sum(decode(entry_user_id,'CV',1,0) as cv, sum(decode(entry_user_id,'SC',1,0) as SC
from vigilance_master group
where entry_user_id=78
group by entry_user_id
>From: "Shyju Narayanan" <shyjukoyyam@gmail.com>
>To: pgsql-sql@postgresql.org
>Subject: [SQL] sql
>Date: Fri, 2 Feb 2007 13:09:09 +0530
>
>Hi All
>
>this is my table ;
>| ID |entry_user_id_int | category_id_chv |
>----------------------------------------------
>| 1 | 78 | CV |
>----------------------------------------------
>| 2 | 78 | VC |
>----------------------------------------------
>| 3 | 78 | CV |
>----------------------------------------------
>| 4 | 78 | CV |
>----------------------------------------------
>| 5 | 78 | CV |
>----------------------------------------------
>| 6 | 78 | CV |
>----------------------------------------------
>| 7 | 78 | CV |
>----------------------------------------------
>| 8 | 78 | CV |
>----------------------------------------------
>| 9 | 78 | VE |
>----------------------------------------------
>| 10 | 78 | CV |
>----------------------------------------------
>| 11 | 78 | SC |
>----------------------------------------------
>
>WHEN "select entry_user_id_int, category_id_chv,count(category_id_chv) from
>vigilance_master group by category_id_chv,entry_user_id_int having"
>entry_user_id_int=78
>result is :
>
>ID entry_user_id_int category_id_chv count
>
>1 78 VC 1
>2 78 VE 1
>3 78 CV 8
>4 78 SC 1
>
>BUT I NEED THE RESULT AS
>entry_user_id_int COUNT(VC) COUNT(VE) COUNT(CV) COUNT(SC) TOTAL
>78 1 1 8 1 11
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Hi...
I tried this its working.. can u please check this.
select count(*) as all, sum(decode(entry_user_id,'VC',1)) as
entry_user_id,sum(decode(entry_user_id,'VE',1)) as VE
,sum(decode(entry_user_id,CV,1))as
CV,sum(decode(entry_user_id,'SC',1))as SC from vigilance_master;
regards
penchal
-----Original Message-----
From: pgsql-sql-owner@postgresql.org
[mailto:pgsql-sql-owner@postgresql.org] On Behalf Of Karthikeyan
Sundaram
Sent: Tuesday, February 06, 2007 12:47 PM
To: shyjukoyyam@gmail.com; pgsql-sql@postgresql.org
Subject: Re: [SQL] sql
try this:
select entry_user_id, sum(decode(entry_user_id,'VC',1,0) as vc, sum(decode(entry_user_id,'VE',1,0) as ve,
sum(decode(entry_user_id,'CV',1,0) as cv, sum(decode(entry_user_id,'SC',1,0) as SC
from vigilance_master group
where entry_user_id=78
group by entry_user_id
>From: "Shyju Narayanan" <shyjukoyyam@gmail.com>
>To: pgsql-sql@postgresql.org
>Subject: [SQL] sql
>Date: Fri, 2 Feb 2007 13:09:09 +0530
>
>Hi All
>
>this is my table ;
>| ID |entry_user_id_int | category_id_chv |
>----------------------------------------------
>| 1 | 78 | CV |
>----------------------------------------------
>| 2 | 78 | VC |
>----------------------------------------------
>| 3 | 78 | CV |
>----------------------------------------------
>| 4 | 78 | CV |
>----------------------------------------------
>| 5 | 78 | CV |
>----------------------------------------------
>| 6 | 78 | CV |
>----------------------------------------------
>| 7 | 78 | CV |
>----------------------------------------------
>| 8 | 78 | CV |
>----------------------------------------------
>| 9 | 78 | VE |
>----------------------------------------------
>| 10 | 78 | CV |
>----------------------------------------------
>| 11 | 78 | SC |
>----------------------------------------------
>
>WHEN "select entry_user_id_int, category_id_chv,count(category_id_chv)
from
>vigilance_master group by category_id_chv,entry_user_id_int having"
>entry_user_id_int=78
>result is :
>
>ID entry_user_id_int category_id_chv count
>
>1 78 VC 1
>2 78 VE 1
>3 78 CV 8
>4 78 SC 1
>
>BUT I NEED THE RESULT AS
>entry_user_id_int COUNT(VC) COUNT(VE) COUNT(CV) COUNT(SC)
TOTAL
>78 1 1 8 1 11
_________________________________________________________________
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