Обсуждение: link problem

hello sir,
      i have printed the contents of a database  on a table using php. how
to give link from each content of cell to another page or file(like
pdf). table in php is been created using printf() statement and i am
unable to insert code to give link for whatever i print.
  thanx in advance
      Arun

On Thu, 28 Feb 2002, arun kv wrote:

>
>
> hello sir,
>       i have printed the contents of a database  on a table using php. how
> to give link from each content of cell to another page or file(like
> pdf). table in php is been created using printf() statement and i am
> unable to insert code to give link for whatever i print.
>   thanx in advance
>       Arun
>
>

At 07:02 28/02/02, Arun wrote:


>hello sir,
>       i have printed the contents of a database  on a table using php. how
>to give link from each content of cell to another page or file(like
>pdf). table in php is been created using printf() statement and i am
>unable to insert code to give link for whatever i print.
>   thanx in advance
>       Arun

How are you fetching the data from your query? If you use pg_fetch_array(),
or one of the related functions, you can pick out the individual data
elements from the array and put whatever formatting you like around them.

best,

Mo


=====
"How can you expect a little child whose mother is an angel and whose
father is a Cannibal King and who has spent her life sailing the seas to
tell the truth always?"
Astrid Lindgren (1907-2002)

On Thu, 2002-02-28 at 00:02, arun kv wrote:
>
>
> hello sir,
>       i have printed the contents of a database  on a table using php. how
> to give link from each content of cell to another page or file(like
> pdf). table in php is been created using printf() statement and i am
> unable to insert code to give link for whatever i print.
>   thanx in advance
>       Arun

  Hi Arun,

  You should review the printf and sprintf documentation. It is a bit
  daunting at first, but makes sense after a bit of work.

  To answser your question as best I can without seeing source code,
  here is one way to make a link using a printf statement

  $link = "http://www.php.net/";
  $text = "PHP Website";
  printf ('<a href="%s">%s</a>', $link, $text);

  Notice that the first %s is replaced with the value of $link,
  while the second %s is replaced with the value of $text.


  It looks like you are just getting started with PHP - you can
  find a lot of helpful resources at http://www.php.net/support.php


  Good Luck and happy PHPing!

--
Zak Greant

MySQL Advocate
PHP Quality Assurance Team