Обсуждение: SQL query question
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Maybe it's to late for me to think correctly (actually I'm sure of that). I'm
going to ask anyways.
I have a table like
id int4
user_id int4
photo varchar
image_type char(1)
where image_type is either G or X
What I want to do is have ONE query that gives me the count of images of each
type per user_id.
So if user 3 has 5 photos of type G and 3 photos of type X
I basically want to have a result 5,3
It got to be possible to get a query like that, but somehow it eludes me
tonight.
Any pointers are greatly appreciated.
UC
- --
Open Source Solutions 4U, LLC 2570 Fleetwood Drive
Phone: +1 650 872 2425 San Bruno, CA 94066
Cell: +1 650 302 2405 United States
Fax: +1 650 872 2417
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Hi Uwe,
I did a solution for you using PLPgSQL,
create or replace function countem() returns varchar as $$
declare
gcount integer;
xcount integer;
result varchar;
begin
select count(*) into gcount
from pix where image_type = 'G';
select count(*) into xcount
from pix where image_type = 'X';
select gcount || ', ' || xcount
into result;
return result;
end;
$$ LANGUAGE plpgsql;
hope this helps, it's simple and always, there's another (better)
solution
it's my first stab at plpgsql so please bear with me.
-----
Jonel Rienton
http://blogs.road14.com
Software Developer, *nix Advocate
On Feb 3, 2005, at 1:32 AM, Uwe C. Schroeder wrote:
> -----BEGIN PGP SIGNED MESSAGE-----
> Hash: SHA1
>
>
> Maybe it's to late for me to think correctly (actually I'm sure of
> that). I'm
> going to ask anyways.
> I have a table like
>
> id int4
> user_id int4
> photo varchar
> image_type char(1)
>
> where image_type is either G or X
> What I want to do is have ONE query that gives me the count of images
> of each
> type per user_id.
> So if user 3 has 5 photos of type G and 3 photos of type X
> I basically want to have a result 5,3
> It got to be possible to get a query like that, but somehow it eludes
> me
> tonight.
>
> Any pointers are greatly appreciated.
>
> UC
>
> - --
> Open Source Solutions 4U, LLC 2570 Fleetwood Drive
> Phone: +1 650 872 2425 San Bruno, CA 94066
> Cell: +1 650 302 2405 United States
> Fax: +1 650 872 2417
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> iD8DBQFCAdOMjqGXBvRToM4RApgvAJsEUsdl6hrVGqRwJ+NI7JrqQqQ5GgCgkTQN
> pavTkx47QUb9nr7XO/r/v5k=
> =B3DH
> -----END PGP SIGNATURE-----
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>
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>
you're right it's late, i better to get to bed myself, i forgot to throw in the parameter for the user_id in there, i'm sure you can figure that one out. regards, ----- Jonel Rienton http://blogs.road14.com Software Developer, *nix Advocate On Feb 3, 2005, at 1:32 AM, Uwe C. Schroeder wrote: > -----BEGIN PGP SIGNED MESSAGE----- > Hash: SHA1 > > > Maybe it's to late for me to think correctly (actually I'm sure of > that). I'm > going to ask anyways. > I have a table like > > id int4 > user_id int4 > photo varchar > image_type char(1) > > where image_type is either G or X > What I want to do is have ONE query that gives me the count of images > of each > type per user_id. > So if user 3 has 5 photos of type G and 3 photos of type X > I basically want to have a result 5,3 > It got to be possible to get a query like that, but somehow it eludes > me > tonight. > > Any pointers are greatly appreciated. > > UC > > - -- > Open Source Solutions 4U, LLC 2570 Fleetwood Drive > Phone: +1 650 872 2425 San Bruno, CA 94066 > Cell: +1 650 302 2405 United States > Fax: +1 650 872 2417 > -----BEGIN PGP SIGNATURE----- > Version: GnuPG v1.2.3 (GNU/Linux) > > iD8DBQFCAdOMjqGXBvRToM4RApgvAJsEUsdl6hrVGqRwJ+NI7JrqQqQ5GgCgkTQN > pavTkx47QUb9nr7XO/r/v5k= > =B3DH > -----END PGP SIGNATURE----- > > > ---------------------------(end of > broadcast)--------------------------- > TIP 2: you can get off all lists at once with the unregister command > (send "unregister YourEmailAddressHere" to > majordomo@postgresql.org) >
# uwe@oss4u.com / 2005-02-02 23:32:28 -0800:
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> Hash: SHA1
>
>
> Maybe it's to late for me to think correctly (actually I'm sure of
> that). I'm going to ask anyways. I have a table like
>
> id int4
> user_id int4
> photo varchar
> image_type char(1)
>
> where image_type is either G or X
> What I want to do is have ONE query that gives me the count of images
> of each type per user_id.
> So if user 3 has 5 photos of type G and 3 photos of type X
> I basically want to have a result 5,3
SELECT COUNT(*) FROM t GROUP BY t.user_id, t.image_type
--
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Am Donnerstag, 3. Februar 2005 08:32 schrieb Uwe C. Schroeder: > Maybe it's to late for me to think correctly (actually I'm sure of > that). I'm going to ask anyways. > I have a table like > > id int4 > user_id int4 > photo varchar > image_type char(1) > > where image_type is either G or X > What I want to do is have ONE query that gives me the count of images > of each type per user_id. > So if user 3 has 5 photos of type G and 3 photos of type X > I basically want to have a result 5,3 > It got to be possible to get a query like that, but somehow it eludes > me tonight. > > Any pointers are greatly appreciated. > > UC select user_id,image_type, count(id) from <table> group by user_id,image_type should do it. -- Markus Schulz