Обсуждение: Anti log in PostgreSQL

Dear all ,

In one of our project I require to calculate antilog of  (3.3234)
But I could not find any functions in Documentation for the same.

In mathematics I would have written it something like

A = antilog (3·3234) = 2144


Any suggestions or  links are most welcome .

Regards,
Vishal Kashyap.

Dear Martin Marques ,

>>In mathematics I would have written it something like
>>
>>A = antilog (3·3234) = 2144
>>
>>
>
>As I can understand, this is a 10 base log, so that what you want is
>10^(3.3234)?
>
>For that you have the exponential operator ^.
>
>
Nope
select exp(3.3234) as a2144
Gives me
27.754555808589792
But the answer expected is
some what near to 2144
The log tables show this

Regards,
Vishal Kashyap.

On Sat, 27 Dec 2003, Sai Hertz And Control Systems wrote:

> select exp(3.3234) as a2144
> Gives me
> 27.754555808589792

Right.  That's e^3.3234

Try:

    select 10^3.3234;

or:

    select dpow(10, 3.3234);

or even:

    select exp(3.3234 * ln(10.0));

--
David.

Dear Martin Marques and other kind people out their ,

>>In mathematics I would have written it something like
>>
>>A = antilog (3·3234) = 2144
>>
>>
>
>As I can understand, this is a 10 base log, so that what you want is
>10^(3.3234)?
>
>
Though antilog did not solve my problem the link below helped me to
prove my point to my bankers

http://www.ilovemaths.com/3depreciation.htm
http://mathforum.org/dr.math/faq/faq.interest.html

Thanks  a load for the kind help forwarded by you all.

Regards,
Vishal Kashyap

>For that you have the exponential operator ^.
>
>
>