On Wed, May 30, 2012 at 11:21 AM, Pavel Stehule
<pavel.stehule@gmail.com> wrote:
Hello
create or replace function call_foo()
returns void as $$
declare r record;
begin
r := foo('Hello');
raise notice ''% %', r.somerow, r.otherinfo;
end;
$$ language plpgsql;
It turns out i also need to define a type for the result record of `foo`, because record can't reveal the structure of the result (it complains: record "r" has no field "somerow").
I have to created this type:
create type foo_result as (somerow SomeTable, otherinfo varchar);
then change `r record;` to `r foo_result;` , no need change `foo` itself, and it works now.
I don't know is this the best way to do this though.
regards
Pavel
2012/5/30 yi huang <yi.codeplayer@gmail.com>:
> I'm porting a oracle function to postgresql, which has signature like this:
>
> FUNCTION foo
> ( seq IN varchar
> , somerow OUT SomeTable
> , otherinfo OUT varchar
> )
>
> It's easy to port this function itself to postgresql, but i have problem to
> execute this function and assign the results into variables:
>
> SELECT (foo(seq)).* INTO (v_somerow, v_otherinfo);
>
> It complains v_somerow can not be row type.
>
> How to handle the result of function foo?
>
> Best regards.
> YiHuang.
--
http://yi-programmer.com/