> On Mon, Aug 25, 2025 at 04:37:21PM -0500, Sami Imseih wrote:
> > When we lookup from shared array only, we need to take a shared lock
> > every lookup. Acquiring that lock is what I am trying to avoid. You
> > are saying it's not worth optimizing that part, correct?
>
> Why do we need a shared lock here? IIUC there's no chance that existing
> entries will change. We'll only ever add new ones to the end.
hmm, can we really avoid a shared lock when reading from shared memory?
considering access for both reads and writes can be concurrent to shared
memory. We are also taking an exclusive lock when writing a new tranche.
--
Sami