Re: [SQL] simple "select / if found" isn't
| От | Jan Otto |
|---|---|
| Тема | Re: [SQL] simple "select / if found" isn't |
| Дата | |
| Msg-id | C9BFAD75-EB0B-4107-A6D9-31ED34D7AF6D@me.com обсуждение исходный текст |
| Ответы |
Re: [SQL] simple "select / if found" isn't
|
| Список | pgsql-sql |
hi gary,
> On 16 Dec 2016, at 12:02, Gary Stainburn <gary.stainburn@ringways.co.uk> wrote:
>
> I'm creating a simple function that must have been done millions of times
> before, but I can't get it to work. In this case, I'm checking a user ID and
> password against previously used passwords:
>
> All I want to do is return 'found' based on the select but I can't get it to
> work.
>
> If I run
>
> select 1 from user_previous_passwords
> where u_id=25 and
> crypt('MyPaSSword',u_previous_password) = u_previous_password;
>
> then it returns the matching row(s)
>
> If I run my function
>
> create or replace function check_previous_passwords (ID int4, PASS varchar)
> returns boolean as $$
> DECLARE
> UID int4;
> BEGIN
> return exists(select 1 from user_previous_passwords
> where u_id=ID and crypt(PASS,u_previous_password) = PASS);
return exists(select 1 from user_previous_passwords where u_id=ID and crypt(PASS,u_previous_password) =
u_previous_password);
> END;
> $$ LANGUAGE plpgsql;
regards, jan
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