On Mon, Dec 8, 2008 at 5:44 PM, Pawel Socha
<pawel.socha@gmail.com> wrote:
2008/12/8 ss_postgres <ss.postgres@gmail.com>:
> Hi,
>
> I am trying to find the position of a character in a string which appears
> multiple times.
>
> The POSITION function returns the position of the character when it first
> occurs.
>
> For eg:
>
> select position ( ' ' in 'Hi How are you');
>
> This returns the result as "3".
>
>
> But i need to result to be
> 3
> 7
> 11
>
>
> Can anyone please let me know what would be the best way to do this.
>
> Thanks
>
merlin=> select distinct(x.case) from (select (case when substring('Hi
How are you' from r for 1) = ' ' then r else null end) from
generate_series(0, length('Hi How are you')) as r) as x;
case
------
3
7
11
--
Pawel Socha
Hi Pawal,
Thanks a lot.
Suppose i need to do the same thing on a column in a table, can you please let me know how to write the query.
Also how to eliminate the null result at the end? For eg: Running the above query gives 4 rows, the last row with null value.
Thanks for your help.