Re: table names seem identical

On 03/07/2012 07:39 AM, Ray Stell wrote:

how I can differentiate these:

oamp=# \z public.c3*                                  Access privilegesSchema |         Name          | Type  | Access privileges | Column access privileges 
--------+-----------------------+-------+-------------------+--------------------------public | c3p0_connection_test  | table |                   | public | c3p0_connection_test  | table |                   | 
(2 rows)

oamp=# select * from pg_tables where tablename = 'c3p0_connection_test';schemaname |      tablename       | tableowner | tablespace | hasindexes | hasrules | hastriggers 
------------+----------------------+------------+------------+------------+----------+-------------public     | c3p0_connection_test | admin      |            | f          | f        | f
(1 row)

oamp=# select version();                                                 version                                                   
------------------------------------------------------------------------------------------------------------PostgreSQL 9.0.7 on i686-pc-linux-gnu, compiled by GCC gcc (GCC) 4.1.2 20080704 (Red Hat 4.1.2-51), 32-bit
(1 row)

do you really want to differentiate or are you just pointing out that it's difficult to tell via \z?

because if you really need to know then you can do

> psql -E temp

temp=# \z test*
********* QUERY **********
SELECT n.nspname as "Schema",
  c.relname as "Name",
  CASE c.relkind WHEN 'r' THEN 'table' WHEN 'v' THEN 'view' WHEN 'S' THEN 'sequence' END as "Type",
  pg_catalog.array_to_string(c.relacl, E'\n') AS "Access privileges",
  pg_catalog.array_to_string(ARRAY(
    SELECT attname || E':\n  ' || pg_catalog.array_to_string(attacl, E'\n  ')
    FROM pg_catalog.pg_attribute a
    WHERE attrelid = c.oid AND NOT attisdropped AND attacl IS NOT NULL
  ), E'\n') AS "Column access privileges"
FROM pg_catalog.pg_class c
     LEFT JOIN pg_catalog.pg_namespace n ON n.oid = c.relnamespace
WHERE c.relkind IN ('r', 'v', 'S')
  AND c.relname ~ '^(test.*)$'
  AND n.nspname !~ '^pg_' AND pg_catalog.pg_table_is_visible(c.oid)
ORDER BY 1, 2;
**************************

                           Access privileges
 Schema | Name  | Type  | Access privileges | Column access privileges
--------+-------+-------+-------------------+--------------------------
 public | test  | table |                   |
 public | test  | table |                   |
(2 rows)


Now you have the query, so alter it to:
SELECT n.nspname as "Schema",
  'x'||c.relname||'x' as "Name",
  CASE c.relkind WHEN 'r' THEN 'table' WHEN 'v' THEN 'view' WHEN 'S' THEN 'sequence' END as "Type",
  pg_catalog.array_to_string(c.relacl, E'\n') AS "Access privileges",
  pg_catalog.array_to_string(ARRAY(
    SELECT attname || E':\n  ' || pg_catalog.array_to_string(attacl, E'\n  ')
    FROM pg_catalog.pg_attribute a
    WHERE attrelid = c.oid AND NOT attisdropped AND attacl IS NOT NULL
  ), E'\n') AS "Column access privileges"
FROM pg_catalog.pg_class c
     LEFT JOIN pg_catalog.pg_namespace n ON n.oid = c.relnamespace
WHERE c.relkind IN ('r', 'v', 'S')
  AND c.relname ~ '^(test.*)$'
  AND n.nspname !~ '^pg_' AND pg_catalog.pg_table_is_visible(c.oid)
ORDER BY 1, 2;

and you'll get:
Schema |  Name   | Type  | Access privileges | Column access privileges
--------+---------+-------+-------------------+--------------------------
 public | xtestx  | table |                   |
 public | xtest x | table |                   |
(2 rows)