Re: How to Declare Functions Containing OUT PArameters?

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От Bill Thoen
Тема Re: How to Declare Functions Containing OUT PArameters?
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Msg-id 4C3E1BCD.1070604@gisnet.com
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Ответ на Re: How to Declare Functions Containing OUT PArameters?  (Tom Lane <tgl@sss.pgh.pa.us>)
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Thanks guys. I think I see now. I was thinking it was a more transparent
pass-by-value / pass-by-reference thing.
Anyway I solved my problem by going back into my comfort zone and
explicitly return a record and I'm not using OUT parameters. They're
aren't what I thought  they were and I'm working on a tight schedule, so
I don't have much toim m eto explre. The compiler seems happier without
them, and when it's happy, I'm happy.

Tom Lane wrote:
> "Joshua D. Drake" <jd@commandprompt.com> writes:
>
>> On Wed, 2010-07-14 at 12:21 -0600, Bill Thoen wrote:
>>
>>> I'm having some difficulty getting plpgsql to recognize a function with
>>> a couple of OUT parameters.
>>>
>
>
>>> psql:ex_out_fail.sql:28: ERROR:  function fishy(text, text, integer,
>>> real) does not exist
>>>
>
>
>> You are passing four IN paramaters. The out paramaters are used in
>> return are they not?
>>
>
> You'd need to do something like
>
> SELECT * INTO num, fnum FROM fishy(str1, str2) ;
>
> OUT parameters in PG are just syntactic sugar for defining a
> record-returning function.  The call syntax still works as if you'd
> written CREATE FUNCTION foo (IN-parameters-only) RETURNS some-record-type.
>
>             regards, tom lane
>
>


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