Re: COUNT(*) to find records which have a certain number of
От
Martin Knipper
Тема
Re: COUNT(*) to find records which have a certain number of
Дата
Msg-id
414F08FD.3080200@mk-os.de
Ответ на
Список
Дерево обсуждения
Re: COUNT(*) to find records which have a certain number of T E Schmitz <mailreg@numerixtechnology.de>
Re: COUNT(*) to find records which have a certain number of Rod Taylor <pg@rbt.ca>
Re: COUNT(*) to find records which have a certain number of T E Schmitz <mailreg@numerixtechnology.de>
Re: COUNT(*) to find records which have a certain number of Martin Knipper <martin@mk-os.de>
Re: COUNT(*) to find records which have a certain number of T E Schmitz <mailreg@numerixtechnology.de>
Re: COUNT(*) to find records which have a certain number of Greg Stark <gsstark@mit.edu>
JOIN performance "Dean Gibson (DB Administrator)" <postgresql3@ultimeth.com>
Re: JOIN performance Tom Lane <tgl@sss.pgh.pa.us>
Re: JOIN performance "Dean Gibson (DB Administrator)" <postgresql3@ultimeth.com>
Re: JOIN performance Tom Lane <tgl@sss.pgh.pa.us>
Re: JOIN performance "Dean Gibson (DB Administrator)" <postgresql3@ultimeth.com>
Re: JOIN performance Tom Lane <tgl@sss.pgh.pa.us>
Re: JOIN performance "Dean Gibson (DB Administrator)" <postgresql3@ultimeth.com>
Re: JOIN performance Tom Lane <tgl@sss.pgh.pa.us>
Re: JOIN performance "Dean Gibson (DB Administrator)" <postgresql3@ultimeth.com>
Is NULLIF nullable? "Dean Gibson (DB Administrator)" <postgresql4@ultimeth.com>
Re: Is NULLIF nullable? "Dean Gibson (DB Administrator)" <postgresql4@ultimeth.com>
Re: JOIN performance Chester Kustarz <chester@arbor.net>
Re: JOIN performance Greg Stark <gsstark@mit.edu>
Am 20.09.2004 18:19 schrieb T E Schmitz: > I figured it eventually. (The only thing I don't know is where to put > the ORDER BY.) > > >>I want to select only those BRAND/MODEL combinations, where the MODEL >>has more than one TYPE, but only where one of those has TYPE_NAME='xyz'. >>I am not interested in MODELs with multiple TYPEs where none of them are >>called 'xyz'. > > Try this: select b.brand_name,m.model_name,count(*) from model m inner join brand b on m.brand_fk=b.brand_pk inner join type t on m.model_pk=t.model_fk where t.type_name='xyz' group by b.brand_name,m.model_name having count(m.model_name)>0; Greetings, Martin -- Martin Knipper www : http://www.mk-os.de Mail : knipper@mk-os.de
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