Re: COUNT(*) to find records which have a certain number of
От
T E Schmitz
Тема
Re: COUNT(*) to find records which have a certain number of
Дата
Msg-id
414F02FF.8000603@numerixtechnology.de
Список
Дерево обсуждения
Re: COUNT(*) to find records which have a certain number of T E Schmitz <mailreg@numerixtechnology.de>
Re: COUNT(*) to find records which have a certain number of Rod Taylor <pg@rbt.ca>
Re: COUNT(*) to find records which have a certain number of T E Schmitz <mailreg@numerixtechnology.de>
Re: COUNT(*) to find records which have a certain number of Martin Knipper <martin@mk-os.de>
Re: COUNT(*) to find records which have a certain number of T E Schmitz <mailreg@numerixtechnology.de>
Re: COUNT(*) to find records which have a certain number of Greg Stark <gsstark@mit.edu>
JOIN performance "Dean Gibson (DB Administrator)" <postgresql3@ultimeth.com>
Re: JOIN performance Tom Lane <tgl@sss.pgh.pa.us>
Re: JOIN performance "Dean Gibson (DB Administrator)" <postgresql3@ultimeth.com>
Re: JOIN performance Tom Lane <tgl@sss.pgh.pa.us>
Re: JOIN performance "Dean Gibson (DB Administrator)" <postgresql3@ultimeth.com>
Re: JOIN performance Tom Lane <tgl@sss.pgh.pa.us>
Re: JOIN performance "Dean Gibson (DB Administrator)" <postgresql3@ultimeth.com>
Re: JOIN performance Tom Lane <tgl@sss.pgh.pa.us>
Re: JOIN performance "Dean Gibson (DB Administrator)" <postgresql3@ultimeth.com>
Is NULLIF nullable? "Dean Gibson (DB Administrator)" <postgresql4@ultimeth.com>
Re: Is NULLIF nullable? "Dean Gibson (DB Administrator)" <postgresql4@ultimeth.com>
Re: JOIN performance Chester Kustarz <chester@arbor.net>
Re: JOIN performance Greg Stark <gsstark@mit.edu>
I figured it eventually. (The only thing I don't know is where to put the ORDER BY.) > I want to select only those BRAND/MODEL combinations, where the MODEL > has more than one TYPE, but only where one of those has TYPE_NAME='xyz'. > I am not interested in MODELs with multiple TYPEs where none of them are > called 'xyz'. SELECT BRAND_NAME,MODEL_NAME FROM TYPE left outer join MODEL on MODEL_PK =TYPE.MODEL_FK left outer join BRAND on BRAND_PK =MODEL.BRAND_FK group by BRAND.BRAND_NAME,MODEL_NAME having count(*)>1 intersect SELECT BRAND_NAME,MODEL.MODEL_NAME FROM TYPE left outer join MODEL on MODEL_PK =TYPE.MODEL_FK left outer join BRAND on BRAND_PK =MODEL.BRAND_FK where TYPE_NAME='xyz' group by BRAND.BRAND_NAME,MODEL_NAME -- Regards/Gruß, Tarlika Elisabeth Schmitz -- Regards/Gruß, Tarlika Elisabeth Schmitz
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От: T E Schmitz
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