Re: Escaping `psql --variable`
От
Alan Gutierrez
Тема
Re: Escaping `psql --variable`
Дата
Msg-id
20120530022055.GB7607@gmail.com
Ответ на
Re: Escaping `psql --variable` (Jeff Davis)
Список
Дерево обсуждения
Escaping `psql --variable` Alan Gutierrez <alan@prettyrobots.com>
Re: Escaping `psql --variable` Jeff Davis <pgsql@j-davis.com>
Re: Escaping `psql --variable` Alan Gutierrez <alan@prettyrobots.com>
On Tue, May 29, 2012 at 05:19:49PM -0700, Jeff Davis wrote: > On Tue, 2012-05-29 at 18:32 -0400, Alan Gutierrez wrote: > > Surprised that this works: > > > > echo ":foo" | psql --variable foo="SELECT 1 AS FOO;" template1 > > > > Why doesn't `psql` escape parameters passed in through `--variable`. When I use > > a library in other languages, they will escape the variable. > > > > How do I use `psql` from `bash` so that it will escape variables and thwart SQL > > injection? > > http://www.postgresql.org/docs/9.1/static/app-psql.html#APP-PSQL-VARIABLES > > In particular, look at the section on SQL Interpolation. Hopefully that > answers your question. > > Regards, > Jeff Davis > Yes. Thank you. To escape a variable and thwart SQL injection: cat <
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