Re: Escaping `psql --variable`
| От | Jeff Davis |
|---|---|
| Тема | Re: Escaping `psql --variable` |
| Дата | |
| Msg-id | 1338337189.28651.25.camel@sussancws0025 обсуждение исходный текст |
| Ответ на | Escaping `psql --variable` (Alan Gutierrez <alan@prettyrobots.com>) |
| Ответы |
Re: Escaping `psql --variable`
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| Список | pgsql-general |
On Tue, 2012-05-29 at 18:32 -0400, Alan Gutierrez wrote: > Surprised that this works: > > echo ":foo" | psql --variable foo="SELECT 1 AS FOO;" template1 > > Why doesn't `psql` escape parameters passed in through `--variable`. When I use > a library in other languages, they will escape the variable. > > How do I use `psql` from `bash` so that it will escape variables and thwart SQL > injection? http://www.postgresql.org/docs/9.1/static/app-psql.html#APP-PSQL-VARIABLES In particular, look at the section on SQL Interpolation. Hopefully that answers your question. Regards, Jeff Davis
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