Re:

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От Sam Mason
Тема Re:
Дата
Msg-id 20090630203711.GP5407@samason.me.uk
обсуждение исходный текст
Ответ на Re:  (Waldemar Bergstreiser <littlesuspense@web.de>)
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On Tue, Jun 30, 2009 at 01:14:10PM +0200, Waldemar Bergstreiser wrote:
> I found a good explanation about informix outer joins.
>
> http://savage.net.au/SQL/outer-joins.html
>
> Please take a look at that.

The syntax appears to make the expression of various idioms difficult;
for example, how would I express the following:

  SELECT *
  FROM a LEFT JOIN b ON a.id = b.id
  WHERE b.id IS NULL OR a.c <> b.d;

Admittedly I don't write code like this very often but, yes, I have used
it on some occasions.  I guess I'd have to resort to a subselect?


I believe this is what Tom was referring to when he said that "there's
no principled way to decide what it *means*".  For example the semantics
of the above are very different from either of:

  SELECT *
  FROM a LEFT JOIN b ON a.id = b.id OR a.c <> b.d
  WHERE b.id IS NULL;

or:

  SELECT *
  FROM a LEFT JOIN b ON a.id = b.id AND (b.id IS NULL OR a.c <> b.d)

and I can't think of any other formulations after reading the link you
gave---it only seems to talk about binary operators involving columns
from two tables.  Second shouldn't be allowed, but I included it in case
I was missing something.

--
  Sam  http://samason.me.uk/

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