Re: join/group/count query.

On Wednesday 20 December 2006 18:06, Hector Villarreal wrote:
> HI in reading this is it possible what was really intended :
> Sum(case when o_model = 5 then 1 else NULL end) as KA
> That would provide a count of all records meeting that condition.
> Otherwise the count( approach will not do that.
>

Because the else is NULL, count does work. Although I would imagine sum will 
also work, count more reflects the logic, i.e. the number of times that 
condition is true
-- 
Gary Stainburn
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