Re: Function to convert bigint to date
| От | Steven Klassen |
|---|---|
| Тема | Re: Function to convert bigint to date |
| Дата | |
| Msg-id | 20041026034636.GA23780@commandprompt.com обсуждение исходный текст |
| Ответ на | Re: Function to convert bigint to date ("Pradeepkumar, Pyatalo (IE10)" <Pradeepkumar.Pyatalo@honeywell.com>) |
| Список | pgsql-novice |
* Pradeepkumar, Pyatalo (IE10) <Pradeepkumar.Pyatalo@honeywell.com> [2004-10-25 02:23:19 -0700]:
> But from the result I need to display only the date and not the
> time. Should I use extract() function to get the day, month and year
> seperately and then form the date format, or is there any other way
> to extract only the date part from the timestamp.
You can cast a timestamp to a date. You really need to give these
things a try yourself. You'd be surprised what you can figure out
through trial and error.
xinu=> select now()::timestamp;
now
----------------------------
2004-10-25 23:45:38.939148
(1 row)
xinu=> select (now()::timestamp)::date;
now
------------
2004-10-25
(1 row)
--
Steven Klassen - Lead Programmer
Command Prompt, Inc. - http://www.commandprompt.com/
PostgreSQL Replication & Support Services, (503) 667-4564
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