How to make this CTE also print rows with 0 as count?

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От air
Тема How to make this CTE also print rows with 0 as count?
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Msg-id 1349527666985-5726792.post@n5.nabble.com
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Ответы Re: How to make this CTE also print rows with 0 as count?  ("David Johnston" <polobo@yahoo.com>)
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I have a CTE based query, to which I pass about 2600 4-tuple
latitude/longitude values using joins - these latitude longitude 4-tuples
have been ID tagged and held in a second table called coordinates. These top
left and bottom right latitude / longitude values are passed into the CTE in
order to display the amount of requests (hourly) made within those
coordinates for given two timestamps).- I am able to get the total requests
per day within the timestamps given, that is, the total count of user
requests on every specified day. (E.g. user opts to see every Wednesday or
Wednesday AND Thursday etc. - between hours 11:55 and 22:04 between dates
January 1 and 31, 2012 for every latitude/longitude 4-tuples I pass.) But I
cannot view the rows with count 0. My query is as below:



WITH v AS (  SELECT '2012-01-1 11:55:11'::timestamp AS _from        ,'2012-01-31 22:02:21'::timestamp AS _to  )
, q AS (  SELECT c.coordinates_id       , date_trunc('hour', t.calltime) AS stamp       , count(*) AS zcount  FROM   v
JOIN  mytable t ON  t.calltime BETWEEN v._from AND v._to                  AND (t.calltime::time >= v._from::time AND
                  t.calltime::time <= v._to::time) AND (extract(DOW
 
from t.calltime) = 3)  JOIN   coordinates c ON (t.lat, t.lon)                   BETWEEN (c.bottomrightlat,
c.topleftlon)                     AND (c.topleftlat, c.bottomrightlon)  GROUP BY c.coordinates_id, date_trunc('hour',
t.calltime) )
 
, cal AS (  SELECT generate_series('2011-2-2 00:00:00'::timestamp                       , '2012-4-1
05:00:00'::timestamp                      , '1 hour'::interval) AS stamp  FROM v  )
 
SELECT q.coordinates_id, cal.stamp::date, sum(q.zcount) AS zcount
FROM   v, cal
LEFT   JOIN q USING (stamp)
WHERE  extract(hour from cal.stamp) >= extract(hour from v._from)
AND    extract(hour from cal.stamp) <= extract(hour from v._to)
AND    extract(DOW from cal.stamp) = 3 
AND    cal.stamp >= v._from
AND    cal.stamp <= v._to
GROUP  BY q.coordinates_id, cal.stamp::date
ORDER  BY q.coordinates_id, stamp;




The output I get when I execute this query is basically like this (normally
I have about 10354 rows returned excluding the rows with 0 zcount, just
providing two coordinates for sake of similarity):

coordinates_id  | stamp      | zcount
1               ;"2012-01-04";      2
1               ;"2012-01-11";      3
1               ;"2012-01-18";      2
2               ;"2012-01-04";      2
2               ;"2012-01-11";      3
2               ;"2012-01-18";      2




However, it should be like this where all rows with zcount 0 should also be
printed out along with rows that have nonzero zcounts -E.g. January 25 with
zcount 0 for the two coordinates with ID 1 and 2 should also be printed in
this small portion of example-:

coordinates_id  | stamp      | zcount
1               ;"2012-01-04";      2
1               ;"2012-01-11";      3
1               ;"2012-01-18";      2
1               ;"2012-01-25";      0
2               ;"2012-01-04";      2
2               ;"2012-01-11";      3
2               ;"2012-01-18";      2
2               ;"2012-01-25";      0




How can I achieve this? Thanks in advance.



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