Re: create index on a field of udt
От | Charles Clavadetscher |
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Тема | Re: create index on a field of udt |
Дата | |
Msg-id | 002801d0b230$8929d9a0$9b7d8ce0$@swisspug.org обсуждение исходный текст |
Ответ на | Re: create index on a field of udt (John R Pierce <pierce@hogranch.com>) |
Ответы |
Re: create index on a field of udt
|
Список | pgsql-general |
Hello
I am not sure it is that simple. Probably you need to create operator classes to be used for indexing.
http://www.postgresql.org/docs/9.4/static/xtypes.html
You are probably better off using the basic data type in your table and using a composite index.
Bye
Charles
From: pgsql-general-owner@postgresql.org [mailto:pgsql-general-owner@postgresql.org] On Behalf Of John R Pierce
Sent: Montag, 29. Juni 2015 07:51
To: pgsql-general@postgresql.org
Subject: Re: [GENERAL] create index on a field of udt
On 6/28/2015 10:31 PM, Shujie Shang wrote:
Oh, I didn't explain my question well, actually I want to create an index on an udt in a table.
e.g.
create type info as (id int, name text);
creat table test (i info);
I want to run:
create index myindex on test (i.id)
create table test of info primary key(id);
or, if you want to use your type plus other stuff in the table, I believe its something like...
create table test (i info, stuff...) primary key (i.id)
or
create index test(i.id);
watch out for ambiguity if the type names match the table or field name. see http://www.postgresql.org/docs/current/static/rowtypes.html#AEN7836
--
john r pierce, recycling bits in santa cruz
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