Обсуждение: Extract only maximum date from column

I want the script to extract only the maximum `next_contact' date and
haven't learned how to do this from my reading of web sites.

The script:

select p.person_nbr, p.company_nbr, c.next_contact
from people as p, contacts as c
where c.next_contact >= '2025-11-01'
group by p.person_nbr, p.company_nbr, c.next_contact
order by p.person_nbr, p.company_nbr, max(c.next_contact);

returns all contacts rather than only the latest one.

Is using a sub-select the proper way?

TIA,

Rich

I believe in general you need

having c.next_contact = max(c.next_contact)

(at least in ANSI SQL) Use having for after the join has occured

I want the script to extract only the maximum `next_contact' date and
haven't learned how to do this from my reading of web sites.

The script:

select p.person_nbr, p.company_nbr, c.next_contact
from people as p, contacts as c
where c.next_contact >= '2025-11-01'
group by p.person_nbr, p.company_nbr, c.next_contact
order by p.person_nbr, p.company_nbr, max(c.next_contact);

returns all contacts rather than only the latest one.

Is using a sub-select the proper way?

TIA,

Rich

I want the script to extract only the maximum `next_contact' date and
haven't learned how to do this from my reading of web sites.

The script:

select p.person_nbr, p.company_nbr, c.next_contact
from people as p, contacts as c
where c.next_contact >= '2025-11-01'
group by p.person_nbr, p.company_nbr, c.next_contact
order by p.person_nbr, p.company_nbr, max(c.next_contact);

returns all contacts rather than only the latest one.

Is using a sub-select the proper way?

On Thu, 4 Dec 2025, Bryan Sayer wrote:

> I believe in general you need
>
> having c.next_contact = max(c.next_contact)
>
> (at least in ANSI SQL) Use having for after the join has occurred

Bryan,

Postgresql didn't like that regardless of where I inserted the `having'
stanza.

Thanks,

Rich

On Thu, 4 Dec 2025, Ron Johnson wrote:

> May not be the only way, but it's how I do it:
> SELECT *
> FROM foo
> WHERE some_dt = (SELECT MAX(some_dt) FROM foo);
>
> It might return more than one row...

Ron,

Didn't quite work for me this way:

select p.person_nbr, p.company_nbr, c.next_contact
from people as p, contacts as c
where c.next_contact (select max(c.next_contact) from c.contacts) >= '2025-11-01'
group by p.person_nbr, p.company_nbr
order by p.person_nbr, p.company_nbr;

Thanks,

Rich

On Thu, 4 Dec 2025, David G. Johnston wrote:

> I would go with a lateral join subquery of the contracts table. Using an
> aggregates to perform ranking is an anti-pattern. You want the contract
> ranked first when ordered by contract_date. Either use a window function
> to explicitly rank the contracts or use a limit/fetch clause to simply
> return the first ordered one.

David,

It's 'contacts' rather than 'contracts'; a minor typo.

I'll read on making a lateral join. Thanks.

> You also seem to have completely missed joining people to contracts -
> suggest using explicit “join” clauses to make that error less likely.

Oops! My bad. Fixed.

Regards,

Rich

You don't include the where clause, just the having clause after the group by.

At least that is what I remember. But it has been awhile.

On Thu, 4 Dec 2025, Bryan Sayer wrote:

I believe in general you need

having c.next_contact = max(c.next_contact)

(at least in ANSI SQL) Use having for after the join has occurred

Bryan,

Postgresql didn't like that regardless of where I inserted the `having'
stanza.

Thanks,

Rich

On Thu, 4 Dec 2025, David G. Johnston wrote:

> I would go with a lateral join subquery of the contracts table. Using an
> aggregates to perform ranking is an anti-pattern. You want the contract
> ranked first when ordered by contract_date. Either use a window function
> to explicitly rank the contracts or use a limit/fetch clause to simply
> return the first ordered one.

David,

I'm closer, but still missing the proper syntax:

select p.person_nbr, p.company_nbr, c.next_contact
from people as p, contacts as c
join lateral (select max(c.next_contact) as last_contact
      where p.person_nbr = c.person_nbr and
      last_contact >= '2025-11-01'
      )
      c on true;

resulting in:
psql:companies-contacted-2025.sql:9: ERROR:  aggregate functions are not allowed in FROM clause of their own query
level
LINE 3: join lateral (select max(c.next_contact) as last_contact

Regards,

Rich

On 12/4/25 1:39 PM, Rich Shepard wrote:
> On Thu, 4 Dec 2025, David G. Johnston wrote:
> 
>> I would go with a lateral join subquery of the contracts table. Using an
>> aggregates to perform ranking is an anti-pattern. You want the contract
>> ranked first when ordered by contract_date. Either use a window function
>> to explicitly rank the contracts or use a limit/fetch clause to simply
>> return the first ordered one.
> 
> David,
> 
> I'm closer, but still missing the proper syntax:
> 
> select p.person_nbr, p.company_nbr, c.next_contact
> from people as p, contacts as c
> join lateral (select max(c.next_contact) as last_contact
>       where p.person_nbr = c.person_nbr and
>       last_contact >= '2025-11-01'
>       )
>       c on true;
> 
> resulting in:
> psql:companies-contacted-2025.sql:9: ERROR:  aggregate functions are not 
> allowed in FROM clause of their own query level
> LINE 3: join lateral (select max(c.next_contact) as last_contact

Would the below work?:

WITH lc AS (SELECT person_nbr, max(next_contact) AS last_contact from 
contacts where next_contact > '2025-11-01' group by c.person_nbr)
select p.person_nbr, p.company_nbr, lc.last_contact from people AS p 
join lc on p.person.nbr = lc.person_nbr;

> 
> Regards,
> 
> Rich
> 
> 

-- 
Adrian Klaver
adrian.klaver@aklaver.com

On Thu, 4 Dec 2025, David G. Johnston wrote:

I would go with a lateral join subquery of the contracts table. Using an
aggregates to perform ranking is an anti-pattern. You want the contract
ranked first when ordered by contract_date. Either use a window function
to explicitly rank the contracts or use a limit/fetch clause to simply
return the first ordered one.

David,

I'm closer, but still missing the proper syntax:

select p.person_nbr, p.company_nbr, c.next_contact
from people as p, contacts as c
join lateral (select max(c.next_contact) as last_contact
     where p.person_nbr = c.person_nbr and
     last_contact >= '2025-11-01'
     )
     c on true;

resulting in:
psql:companies-contacted-2025.sql:9: ERROR:  aggregate functions are not allowed in FROM clause of their own query level
LINE 3: join lateral (select max(c.next_contact) as last_contact

On Thu, 4 Dec 2025, Adrian Klaver wrote:

> Would the below work?:
>
> WITH lc AS (SELECT person_nbr, max(next_contact) AS last_contact from 
> contacts where next_contact > '2025-11-01' group by c.person_nbr)
> select p.person_nbr, p.company_nbr, lc.last_contact from people AS p join lc 
> on p.person.nbr = lc.person_nbr;

Adrian,

Reformated and still has an error:
WITH lc AS (SELECT person_nbr, max(next_contact) AS last_contact
      from contacts where next_contact >= '2025-11-01'
      group by c.person_nbr)
select p.person_nbr, p.company_nbr, lc.last_contact
from people AS p
join lc on p.person.nbr = lc.person_nbr;

psql:companies-contacted-2025.sql:16: ERROR:  missing FROM-clause entry for table "c"
LINE 3:      group by c.person_nbr)

So, tweaking from reported errors:
WITH lc AS (SELECT p.person_nbr, max(c.next_contact) AS last_contact
      from people as p, contacts as c
      where next_contact >= '2025-11-01'
      group by p.person_nbr)
select p.person_nbr, p.company_nbr, lc.last_contact
from people AS p
join lc on p.person.nbr = lc.person_nbr;

psql:companies-contacted-2025.sql:9: ERROR:  missing FROM-clause entry for table "person"
LINE 7: join lc on p.person.nbr = lc.person_nbr;
                    ^
This is obviously a much more complicated query than I expected.

Thanks,

Rich

On Thu, 4 Dec 2025, David G. Johnston wrote:

> As mentioned, the aggregate max should be avoided - you aren’t doing
> statistics, you are ranking.

David,

Got it.

> Select person.*, lastcontact.* from person join lateral (select contact.*
> from contact where contact.person_id=person.person_id order by
> last_contact_date desc limit 1) as lastcontact on true;

Select person.*, lastcontact.*
from people
join lateral (select contact.*
      from contacts
      where contacts.person_nbr = people.person_nbr
      order by last_contact_date
      desc limit 1)
as lastcontact on true;

psql:companies-contacted-2025.sql:10: ERROR:  missing FROM-clause entry for table "contact"
LINE 3: join lateral (select contact.*

So:
Select person.*, lastcontact.*
from people
join lateral (select contacts.*
      from contacts
      where contacts.person_nbr = people.person_nbr
      order by last_contact_date
      desc limit 1)
as lastcontact on true;

psql:companies-contacted-2025.sql:10: ERROR:  column "last_contact_date" does not exist
LINE 6:      order by last_contact_date
                       ^
Regards,

Rich

On Thu, 4 Dec 2025, David G. Johnston wrote:

As mentioned, the aggregate max should be avoided - you aren’t doing
statistics, you are ranking.

David,

Got it.

Select person.*, lastcontact.* from person join lateral (select contact.*
from contact where contact.person_id=person.person_id order by
last_contact_date desc limit 1) as lastcontact on true;

Select person.*, lastcontact.*
from people
join lateral (select contact.*
     from contacts
     where contacts.person_nbr = people.person_nbr
     order by last_contact_date
     desc limit 1)
as lastcontact on true;

psql:companies-contacted-2025.sql:10: ERROR:  missing FROM-clause entry for table "contact"
LINE 3: join lateral (select contact.*

So:
Select person.*, lastcontact.*
from people
join lateral (select contacts.*
     from contacts
     where contacts.person_nbr = people.person_nbr
     order by last_contact_date
     desc limit 1)
as lastcontact on true;

psql:companies-contacted-2025.sql:10: ERROR:  column "last_contact_date" does not exist
LINE 6:      order by last_contact_date
                       

On 12/4/25 14:17, Rich Shepard wrote:
> On Thu, 4 Dec 2025, Adrian Klaver wrote:
> 

> So, tweaking from reported errors:
> WITH lc AS (SELECT p.person_nbr, max(c.next_contact) AS last_contact
>       from people as p, contacts as c
>       where next_contact >= '2025-11-01'
>       group by p.person_nbr)
> select p.person_nbr, p.company_nbr, lc.last_contact
> from people AS p
> join lc on p.person.nbr = lc.person_nbr;
> 
> psql:companies-contacted-2025.sql:9: ERROR:  missing FROM-clause entry 
> for table "person"
> LINE 7: join lc on p.person.nbr = lc.person_nbr;

My mistake should be p.person_nbr

>                     ^
> This is obviously a much more complicated query than I expected.
> 
> Thanks,
> 
> Rich
> 
> 


-- 
Adrian Klaver
adrian.klaver@aklaver.com

> On 4 Dec 2025, at 20:55, Rich Shepard <rshepard@appl-ecosys.com> wrote:
>
> I want the script to extract only the maximum `next_contact' date and
> haven't learned how to do this from my reading of web sites.
>
> The script:
>
> select p.person_nbr, p.company_nbr, c.next_contact
> from people as p, contacts as c
> where c.next_contact >= '2025-11-01'
> group by p.person_nbr, p.company_nbr, c.next_contact
> order by p.person_nbr, p.company_nbr, max(c.next_contact);
>
> returns all contacts rather than only the latest one.
>
> Is using a sub-select the proper way?
>
> TIA,
>
> Rich

That looks like a classical case for a correlated subquery with WHERE NOT EXISTS.

Something like:

select p.person_nbr, p.company_nbr, c.next_contact
from people as p
join contacts as c
on -- I’m really missing some kind of relation between p and c here, I think that’s relevant
where c.next_contact >= ‘2025-11-01’
-- make sure there’s no later contact
and not exists (
    select 1 -- the value is irrelevant, as long as there’s no later instance of a contact
    from contacts c2
    where c2.next_contact >= ‘2025-11-01’
    and c2.next_contact > c.next_contact
)

P.S. My mail-client tried to outsmart me in this reply (in no small part) and I just got back from the pub, so I can’t
exactlyguarantee correctness of the above, but the principal idea should be solid. 

Alban Hertroys
--
There is always an exception to always.