Обсуждение: How to eliminate extra "NOT EXISTS"-query here?
Hi, I'm testing if some dataset contains an array of elements and want to return all “not containing the specified array”, including entries in master table not being referenced.
I have the following schema:
drop table if exists stuff;
drop table if exists test;
CREATE TABLE test(
id varchar primary key
);
create table stuff(
id serial primary key,
test_id varchar NOT NULL REFERENCES test(id),
v varchar not null,
unique (test_id, v)
);
INSERT INTO test(id) values ('a');
INSERT INTO test(id) values ('b');
INSERT INTO test(id) values ('c');
INSERT INTO test(id) values ('d');
INSERT INTO stuff(test_id, v)
values ('a', 'x')
;
INSERT INTO stuff(test_id, v)
values ('b', 'x')
, ('b', 'y')
;
INSERT INTO stuff(test_id, v)
values ('c', 'x')
, ('c', 'y')
, ('c', 'z')
;
select * from test t
WHERE NOT ARRAY['x']::varchar[] <@ (select array_agg(s.v) from stuff s WHERE s.test_id = t.id)
;
select * from test t
WHERE NOT ARRAY['x', 'y']::varchar[] <@ (select array_agg(s.v) from stuff s WHERE s.test_id = t.id)
;
select * from test t
WHERE NOT ARRAY['x', 'y', 'z']::varchar[] <@ (select array_agg(s.v) from stuff s WHERE s.test_id = t.id)
;
select * from test t
WHERE NOT ARRAY ['x', 'y', 'z', 't']::varchar[] <@ (select array_agg(s.v) from stuff s WHERE s.test_id = t.id)
;
-- This works, but I'd rather not do the extra EXISTS
select * from test t
WHERE (NOT ARRAY ['x', 'y', 'z', 't']::varchar[] <@ (select array_agg(s.v) from stuff s WHERE s.test_id = t.id)
OR NOT EXISTS (
select * from stuff s where s.test_id = t.id
)
)
;
So, I want to return all entries in test not having any of ARRAY ['x', 'y', 'z', 't'] referenced in the table stuff, and I'd like to have test.id="d" returned as well, but in order to do that I need to execute the “or not exists”-query. Is it possible to avoid that?
--
Andreas Joseph Krogh
CTO / Partner - Visena AS
Mobile: +47 909 56 963
Вложения
På lørdag 25. november 2023 kl. 17:08:28, skrev Tom Lane <tgl@sss.pgh.pa.us>:
Andreas Joseph Krogh <andreas@visena.com> writes:
> -- This works, but I'd rather not do the extra EXISTS
> select * from test t
> WHERE (NOT ARRAY ['x', 'y', 'z', 't']::varchar[] <@ (select array_agg(s.v) from
> stuffs WHERE s.test_id = t.id)
> OR NOT EXISTS (
> select * from stuff s where s.test_id = t.id
> )
> )
> ;
> So, I want to return all entries in test not having any of ARRAY ['x', 'y',
> 'z', 't'] referenced in the table stuff, and I'd like to have test.id="d"
> returned as well, but in order to do that I need to execute the “or not
> exists”-query. Is it possible to avoid that?
Probably not directly, but perhaps you could improve the performance of
this query by converting the sub-selects into a left join:
select * from test t
left join
(select s.test_id, array_agg(s.v) as arr from stuffs group by s.test_id) ss
on ss.test_id = t.id
WHERE (NOT ARRAY ['x', 'y', 'z', 't']::varchar[] <@ ss.arr)
OR ss.test_id IS NULL;
Another possibility is
...
WHERE (ARRAY ['x', 'y', 'z', 't']::varchar[] <@ ss.arr) IS NOT TRUE
but I don't think that's more readable really, and it will save little.
In either case, this would result in computing array_agg once for
each group of test_id values in "stuffs", while your original computes
a similar aggregate for each row in "test". So whether this is better
depends on the relative sizes of the tables, although my proposal
avoids random access to "stuffs" so it will have some advantage.
regards, tom lane
Excellent, thanks!
--
Andreas Joseph Krogh
CTO / Partner - Visena AS
Mobile: +47 909 56 963
