Обсуждение: BUG #16235: ts_rank ignores match and only considers lower weighted vector

Поиск
Список
Период
Сортировка

BUG #16235: ts_rank ignores match and only considers lower weighted vector

От
PG Bug reporting form
Дата:
The following bug has been logged on the website:

Bug reference:      16235
Logged by:          Dominik Giger
Email address:      dominik.giger@gmail.com
PostgreSQL version: 12.1
Operating system:   Linux
Description:

The following query shows the problem:

select ts_rank(doc1, query) as rank_wrong, ts_rank(doc2, query) as
rank_correct
from (select setweight(to_tsvector('simple', 'foo something'), 'A') ||
             setweight(to_tsvector('simple', 'foobar'), 'C')    as doc1,
             setweight(to_tsvector('simple', 'foo something'), 'A') as
doc2,
             to_tsquery('simple', 'foo:* & something')               as
query) as subquery;

Some more explanation:

doc1 looks like this: 
'foo':1A 'foobar':3C 'something':2A

doc2 looks like this:
'foo':1A 'something':2A

Calling ts_rank on both vectors with the same query
'foo':* & 'something'

Expected result: 
ts_rank on doc1 is the same or higher than ts_rank on doc2.

Actual result: 
ts_rank on doc1 is only half of the rank of doc2. ts_rank seems to only
consider the 'foobar' term with lower weight when calculating the rank. The
foo:1A is only considered in doc2.


Re: BUG #16235: ts_rank ignores match and only considers lower weighted vector

От
Tom Lane
Дата:
PG Bug reporting form <noreply@postgresql.org> writes:
> The following query shows the problem:

> select ts_rank(doc1, query) as rank_wrong, ts_rank(doc2, query) as
> rank_correct
> from (select setweight(to_tsvector('simple', 'foo something'), 'A') ||
>              setweight(to_tsvector('simple', 'foobar'), 'C')    as doc1,
>              setweight(to_tsvector('simple', 'foo something'), 'A') as
> doc2,
>              to_tsquery('simple', 'foo:* & something')               as
> query) as subquery;

> ts_rank on doc1 is only half of the rank of doc2. ts_rank seems to only
> consider the 'foobar' term with lower weight when calculating the rank. The
> foo:1A is only considered in doc2.

No, that's not correct.  What it actually is doing is taking some sort of
average of the weights of the occurrences, as you can see if you play
around with a few more examples besides these two.  That could be better
documented, perhaps, but I don't think it's obviously broken.

I can see that there might be a use for taking the max or even the sum
of the weights rather than an average --- in many situations it wouldn't
be desirable to rank doc1 of your example lower than doc2.  But really
that'd be a different ranking algorithm, not a bug fix for this one.

The manual claims you can write your own ranking algorithm ... but
AFAICS you'd have to code it in C, because we aren't exposing anything
at SQL level that would let you get at the raw match data :-(.
So there's room for improvement there.

Also, you might try using ts_rank_cd() instead, as that uses a different
algorithm for combining the weights.  At least on this example, doc1
gets a higher score than doc2.

            regards, tom lane



Re: BUG #16235: ts_rank ignores match and only considers lowerweighted vector

От
Dominik Giger
Дата:
On Mon, Jan 27, 2020 at 11:35 PM Tom Lane <tgl@sss.pgh.pa.us> wrote:
>
> PG Bug reporting form <noreply@postgresql.org> writes:
> > The following query shows the problem:
>
> > select ts_rank(doc1, query) as rank_wrong, ts_rank(doc2, query) as
> > rank_correct
> > from (select setweight(to_tsvector('simple', 'foo something'), 'A') ||
> >              setweight(to_tsvector('simple', 'foobar'), 'C')    as doc1,
> >              setweight(to_tsvector('simple', 'foo something'), 'A') as
> > doc2,
> >              to_tsquery('simple', 'foo:* & something')               as
> > query) as subquery;
>
> > ts_rank on doc1 is only half of the rank of doc2. ts_rank seems to only
> > consider the 'foobar' term with lower weight when calculating the rank. The
> > foo:1A is only considered in doc2.
>
> No, that's not correct.  What it actually is doing is taking some sort of
> average of the weights of the occurrences, as you can see if you play
> around with a few more examples besides these two.  That could be better
> documented, perhaps, but I don't think it's obviously broken.
>
> I can see that there might be a use for taking the max or even the sum
> of the weights rather than an average --- in many situations it wouldn't
> be desirable to rank doc1 of your example lower than doc2.  But really
> that'd be a different ranking algorithm, not a bug fix for this one.
>
> The manual claims you can write your own ranking algorithm ... but
> AFAICS you'd have to code it in C, because we aren't exposing anything
> at SQL level that would let you get at the raw match data :-(.
> So there's room for improvement there.
>
> Also, you might try using ts_rank_cd() instead, as that uses a different
> algorithm for combining the weights.  At least on this example, doc1
> gets a higher score than doc2.
>
>                         regards, tom lane

I see, thank you for the explanation.

Maybe I can add another reason why I think it might be a bug. Consider
this query:

select ts_rank(doc1, query) as rank_wrong,
       ts_rank(doc2, query) as rank_correct
from (select setweight(to_tsvector('simple', 'foo something'), 'A') ||
             setweight(to_tsvector('simple', 'foobar'), 'C')        as doc1,
             setweight(to_tsvector('simple', 'foo something'), 'A') as doc2,
             to_tsquery('simple', 'foo:*')                          as
query) as subquery;

Here I only removed the '& something' part of the query. Now the query
behaves as one would expect: The first rank is higher than the second.
I am unsure why adding a second search term (which is contained in
both documents) would lead to a change in the ranking order.

What do you think?

Regards,
Dominik Giger