Обсуждение: postgres sql help
hi, i am fairly new in postgresql, so if anyone can help me would be great
if i simply do:
select ver_no
from version
order by ver_no
the result will be something like this:
.1.3.1
.1.3.2.5.
.1.4.1.7.12
.1.4.11.14.7.
.1.4.3.109.1.
.1.4.8.66.
so as you can see first 3 lines are ok, but how to make 1.4.3.109 come before 1.4.11 because the third level "3" is smaller than "11". i understand they are stored as char so i used split_part function to separate each numbers between "." in a separate column. but when i try to convert those column into integer, i am getting an error msg saying: ERROR: invalid input syntax for type numeric: " "
here is my code:
select ver_no, duedate, status,
to_number(split_part(ver_no, '.', 2), '9999') a,
to_number(split_part(ver_no, '.', 3), '9999') b,
to_number(split_part(ver_no, '.', 4), '9999') c,
to_number(split_part(ver_no, '.', 5), '9999') d
from version
order by a,b,c,d
I am not sure if i am heading towards wrong direction but can someone please suggest or give me some other ideas to sort this.
PS: i found some good solution in SQL Server but those commands are not used in postgreSQL.
Thanks in advance
- James
if i simply do:
select ver_no
from version
order by ver_no
the result will be something like this:
.1.3.1
.1.3.2.5.
.1.4.1.7.12
.1.4.11.14.7.
.1.4.3.109.1.
.1.4.8.66.
so as you can see first 3 lines are ok, but how to make 1.4.3.109 come before 1.4.11 because the third level "3" is smaller than "11". i understand they are stored as char so i used split_part function to separate each numbers between "." in a separate column. but when i try to convert those column into integer, i am getting an error msg saying: ERROR: invalid input syntax for type numeric: " "
here is my code:
select ver_no, duedate, status,
to_number(split_part(ver_no, '.', 2), '9999') a,
to_number(split_part(ver_no, '.', 3), '9999') b,
to_number(split_part(ver_no, '.', 4), '9999') c,
to_number(split_part(ver_no, '.', 5), '9999') d
from version
order by a,b,c,d
I am not sure if i am heading towards wrong direction but can someone please suggest or give me some other ideas to sort this.
PS: i found some good solution in SQL Server but those commands are not used in postgreSQL.
Thanks in advance
- James
James Bond <coolofall@hotmail.com> wrote: > hi, i am fairly new in postgresql, so if anyone can help me would be great > > if i simply do: > > select ver_no > from version > order by ver_no > > the result will be something like this: > > .1.3.1 > .1.3.2.5. > .1.4.1.7.12 > .1.4.11.14.7. > .1.4.3.109.1. > .1.4.8.66. > > so as you can see first 3 lines are ok, but how to make 1.4.3.109 come before > 1.4.11 because the third level "3" is smaller than "11". i understand they are > stored as char so i used split_part function to separate each numbers between > "." in a separate column. but when i try to convert those column into integer, > i am getting an error msg saying: ERROR: invalid input syntax for type numeric: > " " > > here is my code: test=*# select * from o; t ---------------.1.3.1.1.3.2.5..1.4.1.7.12.1.4.11.14.7..1.4.3.109.1..1.4.8.66. (6 rows) Time: 0,262 ms test=*# select * from o order by split_part(t,'.',2)::int, split_part(t,'.',3)::int, split_part(t,'.',4)::int; t ---------------.1.3.1.1.3.2.5..1.4.1.7.12.1.4.3.109.1..1.4.8.66..1.4.11.14.7. (6 rows) Time: 0,403 ms Andreas -- Really, I'm not out to destroy Microsoft. That will just be a completely unintentional side effect. (Linus Torvalds) "If I was god, I would recompile penguin with --enable-fly." (unknown) Kaufbach, Saxony, Germany, Europe. N 51.05082°, E 13.56889°
In article <SNT102-W49402A41C6B6599F082D35A8E10@phx.gbl>, James Bond <coolofall@hotmail.com> writes: > hi, i am fairly new in postgresql, so if anyone can help me would be great > if i simply do: > select ver_no > from version > order by ver_no > the result will be something like this: > .1.3.1 > .1.3.2.5. > .1.4.1.7.12 > .1.4.11.14.7. > .1.4.3.109.1. > .1.4.8.66. > so as you can see first 3 lines are ok, but how to make 1.4.3.109 come > before 1.4.11 because the third level "3" is smaller than "11". The query SELECT ver_no FROM version ORDER BY string_to_array(ver_no, '.', '')::int[] should do what you want.
Harald Fuchs <hari.fuchs@gmail.com> wrote:
>> hi, i am fairly new in postgresql, so if anyone can help me would be great
>> if i simply do:
>> select ver_no
>> from version
>> order by ver_no
>> the result will be something like this:
>> .1.3.1
>> .1.3.2.5.
>> .1.4.1.7.12
>> .1.4.11.14.7.
>> .1.4.3.109.1.
>> .1.4.8.66.
>> so as you can see first 3 lines are ok, but how to make 1.4.3.109 come
>> before 1.4.11 because the third level "3" is smaller than "11".
> The query
> SELECT ver_no
> FROM version
> ORDER BY string_to_array(ver_no, '.', '')::int[]
> should do what you want.
Really neat! :-) For pre-9.1, you have to "ORDER BY
string_to_array(TRIM('.' FROM ver_no), '.')::int[];",
though.
Tim