Обсуждение: Howto automatically define collumn names for a function result.

Поиск
Список
Период
Сортировка

Howto automatically define collumn names for a function result.

От
Andreas
Дата:
Hi,
wouldn't it be great to have functions return  "setof something" as 
result where "something" was determined out of the result of a SELECT 
within the function?
like

CREATE OR REPLACE FUNCTION coffee(integer, timestamp, timestamp) RETURNS SETOF
AS
$BODY$   SELECT staff_id, name, room, COUNT(coffee_id) AS cupcount    FROM staff  JOIN coffee_log ON staff_fk =
staff_id   WHERE (staff_id = $1) AND (coffee_time BETWEEN $2 AND $3) GROUP BY staff_id, name, room ORDER BY name;
 
$BODY$ LANGUAGE 'sql' STABLE

There the SELECT dumps a constant set of collumns where as far as I know 
have to be defined as a type to make SETOF happy or define the names 
whenever I call the function which would be tedious.

Actually this is a pretty simple example of some reports I need to produce.
They have around 60 collumns and there is also an aggregate and 
filtering on an id as well as 2 timestamps.
Since the aggregate depends on id and timestamps too, it is no solution 
to build a view and select from that within the function.


Re: Howto automatically define collumn names for a function result.

От
Jorge Godoy
Дата:
Have you tried returning SETOF RECORD[] and using the OUT specification?

CREATE OR REPLACE FUNCTION bla(integer, date, OUT date, OUT integer)
RETURNS SETOF RECORD[] AS
$_$
   SELECT date AS output_date, $1+2 AS next_record FROM table WHERE id = $1 AND start_date >= $2;
$_$ LANGUAGE SQL;


(Just an example code, I haven't tried it myself.  I know it works for plpgsql functions, not sure for sql functions).


Regards,
--
Jorge Godoy     <jgodoy@gmail.com>


On Thu, Aug 27, 2009 at 08:08, Andreas <maps.on@gmx.net> wrote:
Hi,
wouldn't it be great to have functions return  "setof something" as result where "something" was determined out of the result of a SELECT within the function?
like

CREATE OR REPLACE FUNCTION coffee(integer, timestamp, timestamp)
 RETURNS SETOF
AS
$BODY$
  SELECT staff_id, name, room, COUNT(coffee_id) AS cupcount
   FROM staff  JOIN coffee_log ON staff_fk = staff_id
   WHERE (staff_id = $1) AND (coffee_time BETWEEN $2 AND $3)
 GROUP BY staff_id, name, room
 ORDER BY name;
$BODY$
 LANGUAGE 'sql' STABLE

There the SELECT dumps a constant set of collumns where as far as I know have to be defined as a type to make SETOF happy or define the names whenever I call the function which would be tedious.

Actually this is a pretty simple example of some reports I need to produce.
They have around 60 collumns and there is also an aggregate and filtering on an id as well as 2 timestamps.
Since the aggregate depends on id and timestamps too, it is no solution to build a view and select from that within the function.

--
Sent via pgsql-sql mailing list (pgsql-sql@postgresql.org)
To make changes to your subscription:
http://www.postgresql.org/mailpref/pgsql-sql