Обсуждение: create aggregate function 'count_bool( column_name, boolean )'

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create aggregate function 'count_bool( column_name, boolean )'

От
"James Moliere"
Дата:

Hello,
I'd like to create a function called count_bool( column_name, boolean ) in PostgreSQL.

this function is similar to the count( column_name ) function but will only count the trues or falses based on the other input parameter boolean. e.g. if you pass in a 'true', all the trues will be counted but not the falses -- it's the same but opposite if the 'false' was passed in.

I’d like this aggregate function to be developed with the SQL language instead of ‘C’ (for maintenance reasons).  From the surface, it appears to be an incredibly simple job only to find that it's difficult.


In some respects, I can't believe this function doesn't exist in SQL

so now I can create the statement
select distict product_id, count_bool(purchased, true), count_bool(was_selected, true) from some_table group by product_id;

instead of breaking the query into 3 seperate queries

select distict product_id from some_table;
select count(purchased) from product_id where purchased = true;
select count(was_selected) from some_table where was_selected = true;

Am I missing a detail with SQL based aggregate function development?


Any help would be appreciated.

Thanks!

Re: create aggregate function 'count_bool( column_name, boolean )'

От
"Jim Buttafuoco"
Дата:
James,

I know Postgresql doesn't have 2 arg aggregate functions.  what you could do is the following (untested)

select distict product_id, 
sum(case when purchased then 1 else 0 end) as purchased,
sum(case when was_selected then 1 else 0 end) as was_selected
from some_table 
group by product_id;

Jim

---------- Original Message -----------
From: "James Moliere" <jmoliere@ucsd.edu>
To: <pgsql-sql@postgresql.org>
Sent: Fri, 7 Jul 2006 06:53:45 -0700
Subject: [SQL] create aggregate function 'count_bool( column_name, boolean )'

> Hello,
> I'd like to create a function called count_bool( column_name, boolean ) in
> PostgreSQL.
> 
> this function is similar to the count( column_name ) function but will only
> count the trues or falses based on the other input parameter boolean. e.g.
> if you pass in a 'true', all the trues will be counted but not the falses --
> it's the same but opposite if the 'false' was passed in.
> 
> I'd like this aggregate function to be developed with the SQL language
> instead of 'C' (for maintenance reasons).  From the surface, it appears to
> be an incredibly simple job only to find that it's difficult.
> 
> In some respects, I can't believe this function doesn't exist in SQL
> 
> so now I can create the statement
> select distict product_id, count_bool(purchased, true),
> count_bool(was_selected, true) from some_table group by product_id;
> 
> instead of breaking the query into 3 seperate queries
> 
> select distict product_id from some_table;
> select count(purchased) from product_id where purchased = true;
> select count(was_selected) from some_table where was_selected = true;
> 
> Am I missing a detail with SQL based aggregate function development?
> 
> Any help would be appreciated.
> 
> Thanks!
------- End of Original Message -------



Re: create aggregate function 'count_bool( column_name, boolean )'

От
Richard Broersma Jr
Дата:
> so now I can create the statement
> select distict product_id, count_bool(purchased, true),
> count_bool(was_selected, true) from some_table group by product_id;
> 
> instead of breaking the query into 3 seperate queries
> 
> select distict product_id from some_table;
> select count(purchased) from product_id where purchased = true;
> select count(was_selected) from some_table where was_selected = true;
> Am I missing a detail with SQL based aggregate function development?
> Any help would be appreciated.

how about:

select    product_id,    (     select count(purchased)     from some_table as A2     where purchased=true and
A1.product_id=A2.product_id  ) as TP,   (     select count(selected)     from some_table as A3     where purchased=true
andA1.product_id=A3.product_id   ) as TS
 
from some_table as A1
group by product_id;

Regards,

Richard Broersma Jr.