Обсуждение: how to call a function with row-type arg

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how to call a function with row-type arg

От
sad
Дата:
hihow to call a function with a row_type arg ??that is the question

CREATE FUNCTION foo(tablename) returns int .....

SELECT foo ( ??????? );




Re: how to call a function with row-type arg

От
"Richard Hall"
Дата:
<tt>DECLARE</tt><br /><tt>    I INTEGER;</tt><br /><tt>BEGIN</tt><br /><tt>    SELECT *</tt><br /><tt>      INTO
I</tt><br/><tt>      FROM foo( <</tt>tablename><tt> )</tt><p>That part is easy, but I don't understand what you
areusing as a function parameter. <p>Rick <p>sad wrote: <blockquote type="CITE">hi <br /> how to call a function with a
row_typearg ?? <br /> that is the question <p>CREATE FUNCTION foo(tablename) returns int ..... <p>SELECT foo ( ???????
);<p>---------------------------(end of broadcast)--------------------------- <br />TIP 7: don't forget to increase
yourfree space map settings</blockquote> 

Re: how to call a function with row-type arg

От
Tom Lane
Дата:
sad <sad@bankir.ru> writes:
>  how to call a function with a row_type arg ??

> CREATE FUNCTION foo(tablename) returns int .....
SELECT foo(tablename) FROM tablename;
orSELECT foo(tablename.*) FROM tablename;

The first is traditional Postgres usage, but I think the second makes it
more clear what's going on.

BTW, if you use a table alias then the alias is the name to refer to.
SELECT foo(x.*) FROM tablename as x;
        regards, tom lane