Обсуждение: create function problem
I've used the following sql to create the function and
function creation is also successful.
create function usage(text)
returns numeric
as 'select ceil(sum(sessiontime)/60) from ath_online
where loginname=\'$1\' and startdate >= (select
startdate from cst_package where status=\'t\' and
cid=(select cid from cst_customer where
loginname=\'$1\'));'
language 'sql';
executing this function as
select usage('kancha');
returns no records. while executing the query directly
replacke $1 with kancha returns result. Where did i go
wrong ??
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Hi, > create function usage(text) > returns numeric > as 'select ceil(sum(sessiontime)/60) from ath_online > where loginname=\'$1\' and startdate >= (select > startdate from cst_package where status=\'t\' and > cid=(select cid from cst_customer where > loginname=\'$1\'));' > language 'sql'; Try to replace \'$1\' with just $1 (i.e. loginname = $1). Regards -- Matteo Beccati C.R.P. Software S.r.l. http://www.crpsoftware.it/
> Hi, > > > create function usage(text) > > returns numeric > > as 'select ceil(sum(sessiontime)/60) from > ath_online > > where loginname=\'$1\' and startdate >= (select > > startdate from cst_package where status=\'t\' and > > cid=(select cid from cst_customer where > > loginname=\'$1\'));' > > language 'sql'; > > Try to replace \'$1\' with just $1 (i.e. loginname = > $1). > the argument is a string so it has to be enclosed in quotes and \ is to escape the quote. replacing with just $1 will give error like following: Unable to identify an operator '=$' for types 'varchar' and 'int4' You will have to retype this query using an explicit cast __________________________________________________ Do You Yahoo!? Yahoo! Sports - live college hoops coverage http://sports.yahoo.com/
Kancha . wrote:
>
> > Hi,
> >
> > > create function usage(text)
> > > returns numeric
> > > as 'select ceil(sum(sessiontime)/60) from
> > ath_online
> > > where loginname=\'$1\' and startdate >= (select
> > > startdate from cst_package where status=\'t\' and
> > > cid=(select cid from cst_customer where
> > > loginname=\'$1\'));'
> > > language 'sql';
> >
> > Try to replace \'$1\' with just $1 (i.e. loginname =
> > $1).
> >
>
> the argument is a string so it has to be enclosed in
> quotes and \ is to escape the quote. replacing with
> just $1 will give error like following:
The argument is a string and $1 becomes a T_Param node of type "text" in your case, which is a perfectly
valid string without the quotes. Don't get confused by the $ sign in the parameter name. $1 is treated like a
variablename.
Just try "exactly" what was suggested, including the whitespaces surrounding the = operator. Write
loginname = $1
instead of
loginname=$1
This does not only make the code more readable for humans. The parser likes it too.
Jan
>
> Unable to identify an operator '=$' for types
> 'varchar' and 'int4'
> You will have to retype this query using an
> explicit cast
>
>
>
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> Yahoo! Sports - live college hoops coverage
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