Обсуждение: RE: Two table select (fwd)
You could use unions, but I must ask why do you have all those rbldg#
columns in your table?
What's the basic thought behind your database layout?
-DEJ
> -----Original Message-----
> From: Andy [mailto:alewis@mpsi.net]
> Sent: Wednesday, February 03, 1999 1:00 PM
> To: djackson@cpsgroup.com
> Subject: Two table select (fwd)
>
>
> The apts table is at the bottom.
>
> I guess what I am trying to do is to pick each rbldg[x] from
> the referral query
> and then take that and query the apts table for the bldgname.
>
> rbldg[x] is the apt building number and bldgname is the building name.
>
> Thanks
>
> Andy
>
>
>
> I have two queries that I'd like to make as one. Here are the queries:
>
> select * from referral where oid = $some_oid
>
> select bldgname from apts where bldgnum = 'rbldg1'
>
>
> I am trying to get the bldgname from the apts table and want
> to get all of the
> bldgname's including rbldg2, rbldg3, rbldg4. Trying to do it
> in one select
> statment, is this possible?
>
>
>
> table = referral
> +----------------------------------+--------------------------
> --------+-------+
> | rstate | varchar()
> | 2 |
> | rrif | varchar()
> | 10 |
> | rphone | varchar()
> | 20 |
> | rfirstname | varchar()
> | 20 |
> | rlastname | varchar()
> | 25 |
> | rbldg1 | varchar()
> | 10 |
> | rbldgcomment1 | text
> | var |
> | rbldg2 | varchar()
> | 10 |
> | rbldgcomment2 | text
> | var |
> | rbldg3 | varchar()
> | 10 |
> | rbldgcomment3 | text
> | var |
> | rbldg4 | varchar()
> | 10 |
> ....
> +----------------------------------+--------------------------
> --------+-------+
>
> Table = apts
> +----------------------------------+--------------------------
> --------+-------+
> | Field | Type
> | Length|
> +----------------------------------+--------------------------
> --------+-------+
> | bldgnum | varchar()
> | 10 |
> | bldgname | varchar()
> | 35 |
> ...
> +----------------------------------+--------------------------
> --------+-------+
>
> Thanks in advance
>
> Andy
>
>
>
On Wed, 3 Feb 1999, Jackson, DeJuan wrote: >You could use unions, but I must ask why do you have all those rbldg# >columns in your table? >What's the basic thought behind your database layout? > -DEJ The rbldg#'s are holding Apts building numbers and the rbldgcomment#'s are holding the comments for those buildings. Andy > >> -----Original Message----- >> From: Andy [mailto:alewis@mpsi.net] >> Sent: Wednesday, February 03, 1999 1:00 PM >> To: djackson@cpsgroup.com >> Subject: Two table select (fwd) >> >> >> The apts table is at the bottom. >> >> I guess what I am trying to do is to pick each rbldg[x] from >> the referral query >> and then take that and query the apts table for the bldgname. >> >> rbldg[x] is the apt building number and bldgname is the building name. >> >> Thanks >> >> Andy >> >> >> >> I have two queries that I'd like to make as one. Here are the queries: >> >> select * from referral where oid = $some_oid >> >> select bldgname from apts where bldgnum = 'rbldg1' >> >> >> I am trying to get the bldgname from the apts table and want >> to get all of the >> bldgname's including rbldg2, rbldg3, rbldg4. Trying to do it >> in one select >> statment, is this possible? >> >> >> >> table = referral >> +----------------------------------+-------------------------- >> --------+-------+ >> | rstate | varchar() >> | 2 | >> | rrif | varchar() >> | 10 | >> | rphone | varchar() >> | 20 | >> | rfirstname | varchar() >> | 20 | >> | rlastname | varchar() >> | 25 | >> | rbldg1 | varchar() >> | 10 | >> | rbldgcomment1 | text >> | var | >> | rbldg2 | varchar() >> | 10 | >> | rbldgcomment2 | text >> | var | >> | rbldg3 | varchar() >> | 10 | >> | rbldgcomment3 | text >> | var | >> | rbldg4 | varchar() >> | 10 | >> .... >> +----------------------------------+-------------------------- >> --------+-------+ >> >> Table = apts >> +----------------------------------+-------------------------- >> --------+-------+ >> | Field | Type >> | Length| >> +----------------------------------+-------------------------- >> --------+-------+ >> | bldgnum | varchar() >> | 10 | >> | bldgname | varchar() >> | 35 | >> ... >> +----------------------------------+-------------------------- >> --------+-------+ >> >> Thanks in advance >> >> Andy >> >> >> >