Обсуждение: LIKE with no wildcards problem

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LIKE with no wildcards problem

От
"John J. Allison"
Дата:
When doing a select with a LIKE in the where clause,
I always get 0 rows if I do not use a wildcard [_%].
LIKE should act like = in this case (and the docs say so).
A select without a from correctly returns 't'.
I am using PostgreSQL 7.1.3 on Solaris.

What am I missing?
Should I ask pgsql-sql?

Thanks,

John Allison
john@joss.ucar.edu


catalog^> create table foo ( bar char(8) )
CREATE

catalog^> insert into foo values ( 'abc' )
INSERT 38413 1

catalog^> insert into foo values ( '2.20' )
INSERT 38414 1

catalog^> select * from foo
   bar
----------
 abc
 2.20
(2 rows)

catalog^> select * from foo where bar like 'abc'
 bar
-----
(0 rows)

catalog^> select * from foo where bar like 'abc%'
   bar
----------
 abc
(1 row)

catalog^> select 'abc' like 'abc'
 ?column?
----------
 t
(1 row)

Re: LIKE with no wildcards problem

От
Andrew McMillan
Дата:
On Thu, 2002-02-28 at 12:58, John J. Allison wrote:
> When doing a select with a LIKE in the where clause,
> I always get 0 rows if I do not use a wildcard [_%].
> LIKE should act like = in this case (and the docs say so).
> A select without a from correctly returns 't'.
> I am using PostgreSQL 7.1.3 on Solaris.
>
> What am I missing?
> Should I ask pgsql-sql?
>
> Thanks,
>
> John Allison
> john@joss.ucar.edu
>
>
> catalog^> create table foo ( bar char(8) )
> CREATE
>
> catalog^> insert into foo values ( 'abc' )
> INSERT 38413 1
>
> catalog^> insert into foo values ( '2.20' )
> INSERT 38414 1
>
> catalog^> select * from foo
>    bar
> ----------
>  abc
>  2.20
> (2 rows)
>
> catalog^> select * from foo where bar like 'abc'
>  bar
> -----
> (0 rows)

select * from foo where bar like 'abc     ';

char(8) is right-padded with spaces.  Use TEXT, or VARCHAR if you don't
want this sort of effect.

Regards,
                    Andrew.
>
> catalog^> select 'abc' like 'abc'
>  ?column?
> ----------
>  t
> (1 row)

This one will be type text, since no types are specified and that is
what PostgreSQL will prefer internally.

Cheers,
                    Andrew.
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