Обсуждение: best way to convert JSONB object from result
Hi:
I am trying to convert to a Java or Map objectfrom resultset with a jsonb column.
Currently, I am using
String jsonString = resultSet.getString("jsonb_column_name")
then I convert from jsonString to a Map<String,Object> or a Java class object.
This is obviously inefficient. What would be most efficient (not too complicated)
Thanks in Advance
Use boon,jackson or some other json parser to parse it into an object.
On 19 August 2015 at 15:20, Tom Smith <tomsmith1989sk@gmail.com> wrote:
Hi:I am trying to convert to a Java or Map objectfrom resultset with a jsonb column.Currently, I am usingString jsonString = resultSet.getString("jsonb_column_name")then I convert from jsonString to a Map<String,Object> or a Java class object.This is obviously inefficient. What would be most efficient (not too complicated)Thanks in Advance
You are using the most efficient way. I tried to look into converting the jsonb value directly to some json parser in the jdbc driver, but it turned out the the server always sends jsonb as a serialized string instead of the faster-to-parse internal jsonb storage format.
-Mikko
From: pgsql-jdbc-owner@postgresql.org <pgsql-jdbc-owner@postgresql.org> on behalf of Tom Smith <tomsmith1989sk@gmail.com>
Sent: 19 August 2015 22:20
To: pgsql-jdbc@postgresql.org
Subject: [JDBC] best way to convert JSONB object from result
Sent: 19 August 2015 22:20
To: pgsql-jdbc@postgresql.org
Subject: [JDBC] best way to convert JSONB object from result
Hi:
I am trying to convert to a Java or Map objectfrom resultset with a jsonb column.
Currently, I am using
String jsonString = resultSet.getString("jsonb_column_name")
then I convert from jsonString to a Map<String,Object> or a Java class object.
This is obviously inefficient. What would be most efficient (not too complicated)
Thanks in Advance