Обсуждение: create c function with void argument bug?

Hello,

It seems that this:
CREATE OR REPLACE FUNCTION test_fsync_speed() RETURNS float AS '$libdir/test_fsync_speed','\
test_fsync_speed' LANGUAGE C IMMUTABLE STRICT;

is not equivalent to this (note "void" argument):

CREATE OR REPLACE FUNCTION test_fsync_speed(void) RETURNS float AS '$libdir/test_fsync_speed','\
test_fsync_speed' LANGUAGE C IMMUTABLE STRICT;

Two functions are created.
test=# \df                             List of functionsSchema |       Name       | Result data type | Argument data
types|  Type   
--------+------------------+------------------+---------------------+--------public | test_fsync_speed | double
precision|                     | normalpublic | test_fsync_speed | double precision | void                | normal 

Furthermore, I can't figure out how to call the "void" argument variant. Why is void accepted as an argument?

create function testvoid(void) returns void as '' LANGUAGE PLPGSQL;
ERROR:  PL/pgSQL functions cannot accept type void

I punched the void argument in just by chance- am I just stupid?

Cheers,
M

"A.M." <agentm@themactionfaction.com> writes:
> It seems that this:
> CREATE OR REPLACE FUNCTION test_fsync_speed() RETURNS float AS '$libdir/test_fsync_speed','\
> test_fsync_speed' LANGUAGE C IMMUTABLE STRICT;

> is not equivalent to this (note "void" argument):

> CREATE OR REPLACE FUNCTION test_fsync_speed(void) RETURNS float AS '$libdir/test_fsync_speed','\
> test_fsync_speed' LANGUAGE C IMMUTABLE STRICT;

Why would you think it would be?  "void" in SQL doesn't act the same way
as "void" in C, it's an actual type.
        regards, tom lane