Обсуждение: date_trunc problem in HEAD

Hey All,

I goofed with the patch I submitted last year for adding 'week' capability to
the date_trunc function.

Attached is a patch against HEAD for your review.

Cheers,
Rob

--
 11:00:49 up 47 days, 16:17,  4 users,  load average: 3.01, 2.37, 2.37
Linux 2.6.5-02 #8 SMP Mon Jul 12 21:34:44 MDT 2004

On Sun, Mar 13, 2005 at 11:12:32AM -0700, Robert Creager wrote:
> 
> Hey All,
> 
> I goofed with the patch I submitted last year for adding 'week' capability to
> the date_trunc function.
> 
> Attached is a patch against HEAD for your review.

It has this comment in it:                              /* the new year cannot be greater than the
        * original year, so we subtract one if it is
 

Can you please explain that?

The "iso" year can be both greater and smaller than the current
year.


Kurt

When grilled further on (Sun, 13 Mar 2005 19:40:02 +0100),
Kurt Roeckx <kurt@roeckx.be> confessed:

> > Attached is a patch against HEAD for your review.
> 
> It has this comment in it:
>                                /* the new year cannot be greater than the
>                                 * original year, so we subtract one if it is
> 

Not doing to well here.  When will the ISO year be greater than the current
year?  But, what I did is incorrect and 2006-01-01 shows the next problem date:

SELECT '' AS date_trunc_week, date_trunc( 'week', timestamp '2006-01-01' ) AS
week_trunc;
date_trunc_week |     week_trunc      
-----------------+---------------------                | 2006-12-25 00:00:00

Heck, even what I submitted, test and all is wrong:

SELECT '' AS date_trunc_week, date_trunc( 'week', timestamp '2005-01-01' ) AS
week_trunc;date_trunc_week |     week_trunc      
-----------------+---------------------                | 2005-01-02 00:00:00

The date should be 2005-01-03.  Sigh. Maybe I should of just submitted a bug
report about it...

So, unless someone else knows how to do this correctly, I'll have to actually
think about it.

Cheers,
Rob

-- 12:34:02 up 47 days, 17:50,  4 users,  load average: 2.34, 2.60, 2.55
Linux 2.6.5-02 #8 SMP Mon Jul 12 21:34:44 MDT 2004

On Sun, Mar 13, 2005 at 12:48:00PM -0700, Robert Creager wrote:
> When grilled further on (Sun, 13 Mar 2005 19:40:02 +0100),
> Kurt Roeckx <kurt@roeckx.be> confessed:
> 
> > > Attached is a patch against HEAD for your review.
> > 
> > It has this comment in it:
> >                                /* the new year cannot be greater than the
> >                                 * original year, so we subtract one if it is
> > 
> 
> Not doing to well here.  When will the ISO year be greater than the current
> year?  But, what I did is incorrect and 2006-01-01 shows the next problem date:

The iso year can be greater than the current year at the end of
the year and smaller on the start of the year.  You have either
of those at every year change.

> SELECT '' AS date_trunc_week, date_trunc( 'week', timestamp '2006-01-01' ) AS
> week_trunc;
> 
>  date_trunc_week |     week_trunc      
> -----------------+---------------------
>                  | 2006-12-25 00:00:00

I expected 2005-12-26 here.

> SELECT '' AS date_trunc_week, date_trunc( 'week', timestamp '2005-01-01' ) AS
> week_trunc;
>  date_trunc_week |     week_trunc      
> -----------------+---------------------
>                  | 2005-01-02 00:00:00

That's a higher date, and obviouly looks wrong.  Here I expected
2004-12-27

> The date should be 2005-01-03.  Sigh. Maybe I should of just submitted a bug
> report about it...

That's the next week, and not what I would expect to get as
result.


Kurt

OK.  I believe the following function provides the correct functionality. 
Agree/disagree?  If it's good, I'll figure out how to convert this little
monster to C...

CREATE OR REPLACE FUNCTION 
date_trunc_week(timestamp without time zone)
RETURNS timestamp without time zone   AS '
DECLARE  reading_time ALIAS FOR $1;  year timestamp;  dow integer;  temp interval;  weeks text;  adjust text;
BEGIN  year := date_trunc( ''year''::text, reading_time );  dow := date_part( ''dow'', year );  IF dow >= 4 THEN
adjust:= 1 - dow || '' day'';  ELSIF dow != 1 THEN     adjust := dow - 6 || '' day'';  ELSE     adjust := ''0 day'';
ENDIF;  temp := reading_time - (year + adjust::interval);               weeks := trunc(date_part( ''days'', temp ) / 7)
||'' weeks'';  RETURN year + adjust::interval + weeks::interval;
 
END;
' LANGUAGE plpgsql;


select date_trunc_week( '2004-01-01' ); -- 2003-12-29 00:00:00
select date_trunc_week( '2005-01-01' ); -- 2004-12-27 00:00:00
select date_trunc_week( '2005-06-01' ); -- 2005-05-30 00:00:00
select date_trunc_week( '2006-01-01' ); -- 2005-12-26 00:00:00
select date_trunc_week( '2007-01-01' ); -- 2007-01-01 00:00:00

Thanks for your input on this Kurt.

Cheers,
Rob

-- 21:48:49 up 48 days,  3:05,  4 users,  load average: 3.80, 3.13, 2.82
Linux 2.6.5-02 #8 SMP Mon Jul 12 21:34:44 MDT 2004