Обсуждение: AW: [HACKERS] having and union in v7beta

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AW: [HACKERS] having and union in v7beta

От
Zeugswetter Andreas SB
Дата:
>> play=> explain select * from comuni union select * from comuni;
> *However*, we have not fixed the bug that causes "select foo union
> select foo" to be incorrectly simplified --- the UNION code is still
> applying cnfify.  (Which it probably shouldn't, but I haven't wanted
> to touch that code until I have the time to rewrite it completely.)
> The reason 7.0beta1 generates the "right" answer is that it has a
> recently-introduced bug in the comparison routines that causes it to
> think the two select subqueries aren't the same.

But if the two queries are the same, the union CAN be simplified,
since the union of two identical masses (I don't know the correct word here)
is still that one mass.

Thus 6.5 simplification is correct in this particular case.

Andreas


Re: AW: [HACKERS] having and union in v7beta

От
Tom Lane
Дата:
Zeugswetter Andreas SB <ZeugswetterA@Wien.Spardat.at> writes:
>>> play=> explain select * from comuni union select * from comuni;

>> *However*, we have not fixed the bug that causes "select foo union
>> select foo" to be incorrectly simplified --- the UNION code is still
>> applying cnfify.

> But if the two queries are the same, the union CAN be simplified,
> since the union of two identical masses (I don't know the correct word here)
> is still that one mass.

> Thus 6.5 simplification is correct in this particular case.

No, it is NOT right, because we're dealing with multisets not sets
(I think "set" is the English word you were looking for).

The SQL spec specifies that UNION implies DISTINCT, ie, removal of
duplicate rows:
             i) Let R be a row that is a duplicate of some row in T1 or of                some row in T2 or both. Let m
bethe number of duplicates                of R in T1 and let n be the number of duplicates of R in                T2,
wherem  ii) If ALL is not specified, then
 
                Case:
                1) If UNION is specified, then
                  Case:
                  A) If m > 0 or n > 0, then T contains exactly one dupli-                     cate of R.
                  B) Otherwise, T contains no duplicate of R.

If query "select foo" would produce X, Y, Y, Z, then the correct result
of "select foo UNION select foo" is X, Y, Z.  But that's not what 6.5
will give you.

I think it would be correct to simplify the union to "select DISTINCT foo"
but that requires all-new simplification code, as well as some thought
about how it'd interact with any DISTINCT or DISTINCT ON already present.
        regards, tom lane


Re: AW: [HACKERS] having and union in v7beta

От
Peter Eisentraut
Дата:
On Thu, 2 Mar 2000, Zeugswetter Andreas SB wrote:

> But if the two queries are the same, the union CAN be simplified,
> since the union of two identical masses (I don't know the correct word here)
> is still that one mass.

"set" :)

> 
> Thus 6.5 simplification is correct in this particular case.

The issue here seems to be that the queries could have side-effects, such
as

select nextval('sequence1') union
select nextval('sequence1')

which should arguably return two distinct rows. I gotta reread SQL's
opinion on this, but I'm sure Tom has already done that. From a
mathematical point of view, I believe your assumption "lexically equal
queries yield mathematically equal sets" is wrong.

-- 
Peter Eisentraut                  Sernanders väg 10:115
peter_e@gmx.net                   75262 Uppsala
http://yi.org/peter-e/            Sweden