Обсуждение: Query Question
I have two tables
Table "public.mailings"
Column | Type | Modifiers
--------+-------------------+-----------
key | character varying |
name | character varying |
Table "public.userdata"
Column | Type | Modifiers
--------+-------------------+-----------
key | character varying |
uid | character varying |
name | character varying |
which hold the following data
mailing:
key | name
-----+--------
A1 | Test 1
A2 | Test 2
A3 | Test 3
A4 | Test 4
userdata:
key | uid | name
-----+-----+--------
A1 | B1 | Test 1
A3 | B1 | Test 3
A2 | B2 | Test 2
A3 | B2 | Test 3
A4 | B2 | Test 4
A2 | B2 | Test 2
A1 | B3 | Test 1
A4 | B3 | Test 4
A1 | B4 | Test 1
A2 | B5 | Test 2
A3 | B5 | Test 3
A4 | B5 | Test 4
A1 | B6 | Test 1
A2 | B6 | Test 2
A3 | B6 | Test 3
A4 | B6 | Test 4
I want to select the data between userdata and mailings, that adds me
a null row to the mailings if mailing table does not have a matching
row for "key" in the grouping "uid".
So eg the result should look like this
key | name | key | uid | name
-----+--------+-----+-----+--------
A1 | Test 1 | A1 | B1 | Test 1
A2 | Test 2 | | |
A3 | Test 3 | A3 | B1 | Test 3
A4 | Test 4 | | |
A1 | Test 1 | | |
A2 | Test 2 | A2 | B2 | Test 2
A2 | Test 2 | A2 | B2 | Test 2
A3 | Test 3 | A3 | B2 | Test 3
A4 | Test 4 | A4 | B2 | Test 4
...
but my problem is, that a normal join will not work, because both
tables will hold a complete set of matching "key" data. I need to sub
group the join through the "uid" column from the userdata.
But i have no idea how to do this. Any idea if there is a simple way to do this?
--
[ Clemens Schwaighofer -----=====:::::~ ]
Advertising Age Global Agency of the Year 2008
Adweek Global Agency of the Year 2008
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Try working with this:
SELECT m.key AS mailings_key,
m.name AS mailings_name,
COALESCE(u.key,'') AS userdata_key,
COALESCE(u.uid,'') AS userdata_uid,
COALESCE(u.name,'') AS userdata_name
FROM (SELECT m0.key, m0.name, u0.uid
FROM mailings m0, (SELECT DISTINCT uid FROM userdata) AS u0
ORDER BY u0.uid, m0.key) AS m
LEFT OUTER JOIN userdata u ON u.key = m.key AND u.uid = m.uid
ORDER BY m.uid, m.key
Cheers,
Ioana
--- On Tue, 2/10/09, Schwaighofer Clemens <clemens.schwaighofer@tequila.jp> wrote:
> From: Schwaighofer Clemens <clemens.schwaighofer@tequila.jp>
> Subject: [GENERAL] Query Question
> To: pgsql-general@postgresql.org
> Received: Tuesday, February 10, 2009, 5:30 AM
> I have two tables
>
> Table "public.mailings"
> Column | Type | Modifiers
> --------+-------------------+-----------
> key | character varying |
> name | character varying |
>
> Table "public.userdata"
> Column | Type | Modifiers
> --------+-------------------+-----------
> key | character varying |
> uid | character varying |
> name | character varying |
>
> which hold the following data
>
> mailing:
>
> key | name
> -----+--------
> A1 | Test 1
> A2 | Test 2
> A3 | Test 3
> A4 | Test 4
>
> userdata:
>
> key | uid | name
> -----+-----+--------
> A1 | B1 | Test 1
> A3 | B1 | Test 3
> A2 | B2 | Test 2
> A3 | B2 | Test 3
> A4 | B2 | Test 4
> A2 | B2 | Test 2
> A1 | B3 | Test 1
> A4 | B3 | Test 4
> A1 | B4 | Test 1
> A2 | B5 | Test 2
> A3 | B5 | Test 3
> A4 | B5 | Test 4
> A1 | B6 | Test 1
> A2 | B6 | Test 2
> A3 | B6 | Test 3
> A4 | B6 | Test 4
>
> I want to select the data between userdata and mailings,
> that adds me
> a null row to the mailings if mailing table does not have a
> matching
> row for "key" in the grouping "uid".
>
> So eg the result should look like this
>
> key | name | key | uid | name
> -----+--------+-----+-----+--------
> A1 | Test 1 | A1 | B1 | Test 1
> A2 | Test 2 | | |
> A3 | Test 3 | A3 | B1 | Test 3
> A4 | Test 4 | | |
> A1 | Test 1 | | |
> A2 | Test 2 | A2 | B2 | Test 2
> A2 | Test 2 | A2 | B2 | Test 2
> A3 | Test 3 | A3 | B2 | Test 3
> A4 | Test 4 | A4 | B2 | Test 4
> ...
>
> but my problem is, that a normal join will not work,
> because both
> tables will hold a complete set of matching "key"
> data. I need to sub
> group the join through the "uid" column from the
> userdata.
>
> But i have no idea how to do this. Any idea if there is a
> simple way to do this?
>
> --
> [ Clemens Schwaighofer
> -----=====:::::~ ]
>
> Advertising Age Global Agency of the Year 2008
> Adweek Global Agency of the Year 2008
>
> This e-mail is intended only for the named person or entity
> to which
> it is addressed and contains valuable business information
> that is
> privileged, confidential and/or otherwise protected from
> disclosure.
> Dissemination, distribution or copying of this e-mail or
> the
> information herein by anyone other than the intended
> recipient, or
> an employee or agent responsible for delivering the message
> to the
> intended recipient, is strictly prohibited. All contents
> are the
> copyright property of TBWA Worldwide, its agencies or a
> client of
> such agencies. If you are not the intended recipient, you
> are
> nevertheless bound to respect the worldwide legal rights of
> TBWA
> Worldwide, its agencies and its clients. We require that
> unintended
> recipients delete the e-mail and destroy all electronic
> copies in
> their system, retaining no copies in any media.If you have
> received
> this e-mail in error, please immediately notify us via
> e-mail to
> disclaimer@tbwaworld.com. We appreciate your cooperation.
>
> We make no warranties as to the accuracy or completeness of
> this
> e-mail and accept no liability for its content or use. Any
> opinions
> expressed in this e-mail are those of the author and do not
>
> necessarily reflect the opinions of TBWA Worldwide or any
> of its
> agencies or affiliates.
>
>
> --
> Sent via pgsql-general mailing list
> (pgsql-general@postgresql.org)
> To make changes to your subscription:
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On 02/11/2009 01:10 AM, Ioana Danes wrote: > Try working with this: > > SELECT m.key AS mailings_key, > m.name AS mailings_name, > COALESCE(u.key,'') AS userdata_key, > COALESCE(u.uid,'') AS userdata_uid, > COALESCE(u.name,'') AS userdata_name > FROM (SELECT m0.key, m0.name, u0.uid > FROM mailings m0, (SELECT DISTINCT uid FROM userdata) AS u0 > ORDER BY u0.uid, m0.key) AS m > LEFT OUTER JOIN userdata u ON u.key = m.key AND u.uid = m.uid > ORDER BY m.uid, m.key Great, this one works too! > Cheers, > Ioana > > --- On Tue, 2/10/09, Schwaighofer Clemens <clemens.schwaighofer@tequila.jp> wrote: > >> From: Schwaighofer Clemens <clemens.schwaighofer@tequila.jp> >> Subject: [GENERAL] Query Question >> To: pgsql-general@postgresql.org >> Received: Tuesday, February 10, 2009, 5:30 AM >> I have two tables >> >> Table "public.mailings" >> Column | Type | Modifiers >> --------+-------------------+----------- >> key | character varying | >> name | character varying | >> >> Table "public.userdata" >> Column | Type | Modifiers >> --------+-------------------+----------- >> key | character varying | >> uid | character varying | >> name | character varying | >> >> which hold the following data >> >> mailing: >> >> key | name >> -----+-------- >> A1 | Test 1 >> A2 | Test 2 >> A3 | Test 3 >> A4 | Test 4 >> >> userdata: >> >> key | uid | name >> -----+-----+-------- >> A1 | B1 | Test 1 >> A3 | B1 | Test 3 >> A2 | B2 | Test 2 >> A3 | B2 | Test 3 >> A4 | B2 | Test 4 >> A2 | B2 | Test 2 >> A1 | B3 | Test 1 >> A4 | B3 | Test 4 >> A1 | B4 | Test 1 >> A2 | B5 | Test 2 >> A3 | B5 | Test 3 >> A4 | B5 | Test 4 >> A1 | B6 | Test 1 >> A2 | B6 | Test 2 >> A3 | B6 | Test 3 >> A4 | B6 | Test 4 >> >> I want to select the data between userdata and mailings, >> that adds me >> a null row to the mailings if mailing table does not have a >> matching >> row for "key" in the grouping "uid". >> >> So eg the result should look like this >> >> key | name | key | uid | name >> -----+--------+-----+-----+-------- >> A1 | Test 1 | A1 | B1 | Test 1 >> A2 | Test 2 | | | >> A3 | Test 3 | A3 | B1 | Test 3 >> A4 | Test 4 | | | >> A1 | Test 1 | | | >> A2 | Test 2 | A2 | B2 | Test 2 >> A2 | Test 2 | A2 | B2 | Test 2 >> A3 | Test 3 | A3 | B2 | Test 3 >> A4 | Test 4 | A4 | B2 | Test 4 >> ... >> >> but my problem is, that a normal join will not work, >> because both >> tables will hold a complete set of matching "key" >> data. I need to sub >> group the join through the "uid" column from the >> userdata. >> >> But i have no idea how to do this. Any idea if there is a >> simple way to do this? -- [ Clemens Schwaighofer -----=====:::::~ ] [ IT Engineer/Web Producer/Planning/Manager ] [ E-Graphics Communications SP Digital ] [ 6-17-2 Ginza Chuo-ku, Tokyo 104-8167, JAPAN ] [ Tel: +81-(0)3-3545-7706 Fax: +81-(0)3-3545-7343 ] [ http://www.e-gra.co.jp ]