Обсуждение: Elegant copy of a row using PL
Hi! I'm not sure about the English terminology for that so I'm sorry if I made a mistake on the subject and on this message. I've a table with 50 colums. I want to copy a certain row using PL and change only 2 values. The way to do it with insertis to long. Is there any other elegant way? Thank you very much Richard -- "Feel free" - 5 GB Mailbox, 50 FreeSMS/Monat ... Jetzt GMX ProMail testen: http://www.gmx.net/de/go/promail
On 1/16/07, richard lavoie <richard_lavoie@gmx.de> wrote: > Hi! > > > I'm not sure about the English terminology for that so I'm sorry if I made a > mistake on the subject and on this message. > > I've a table with 50 colums. I want to copy a certain row using PL and change only 2 values. The way to do it with insertis to long. Is there any other elegant way? the basic methodology is to: insert select into a scratch table; update scratch table; insert select back into real_table; scratch can be a persistent table (remember to truncate it) or a temp table. if it is a temp, remember to create it before you call your pl for the first time in a session. merlin
"Merlin Moncure" <mmoncure@gmail.com> writes:
> On 1/16/07, richard lavoie <richard_lavoie@gmx.de> wrote:
>> I've a table with 50 colums. I want to copy a certain row using PL and change only 2 values. The way to do it with
insertis to long. Is there any other elegant way?
> the basic methodology is to:
> insert select into a scratch table;
> update scratch table;
> insert select back into real_table;
> scratch can be a persistent table (remember to truncate it) or a temp
> table. if it is a temp, remember to create it before you call your pl
> for the first time in a session.
Also, I think in 8.2 you could use a record variable in plpgsql.
declare r record;
select * into r from src where ...;
r.foo = whatever;
r.bar = whatever;
insert into dest values(r.*);
regards, tom lane