Обсуждение: Newbie question about escaping in a function
I have a simple function defined thusly:
CREATE OR REPLACE FUNCTION datemath(timestamp with time zone, int4, varchar)
RETURNS timestamp AS
'
DECLARE
tdat timestamp;
rdat timestamp;
BEGIN
IF ($1 IS NULL) THEN
TDAT := NOW();
ELSE
TDAT := $1;
END IF;
select tdat + interval ''$2 $3'' into rdat;
return rdat;
END;
'
LANGUAGE 'plpgsql' VOLATILE;
The problem is the interval part. How do I tell the bugger to use the second and third params as input to interval? I have tried different ways of escaping, from \’$2 $3\’ to ‘’$2 $3’’ and everything else in between, it just doesn’t like it.
Help! J
Thanks,
naeem
On Tue, 2004-10-26 at 11:57 -0500, Naeem Bari wrote:
> I have a simple function defined thusly:
>
>
>
> CREATE OR REPLACE FUNCTION datemath(timestamp with time zone, int4,
> varchar)
>
> RETURNS timestamp AS
>
> '
>
> DECLARE
>
> tdat timestamp;
>
> rdat timestamp;
>
> BEGIN
>
> IF ($1 IS NULL) THEN
>
> TDAT := NOW();
>
> ELSE
>
> TDAT := $1;
>
> END IF;
It's neater to use the COALESCE() function, which is designed expressly
for this.
> select tdat + interval ''$2 $3'' into rdat;
In PL/pgSQL that should be "select into rdat ..."; but that won't work
in any case because you can't use passed parameters inside a string like
that.
> return rdat;
>
> END;
>
> '
>
> LANGUAGE 'plpgsql' VOLATILE;
>
>
>
> The problem is the interval part. How do I tell the bugger to use the
> second and third params as input to interval? I have tried different
> ways of escaping, from \’$2 $3\’ to ‘’$2 $3’’ and everything else in
> between, it just doesn’t like it.
You have to construct a command string and use EXECUTE:
CREATE OR REPLACE FUNCTION datemath(timestamp with time zone, int4, varchar)
RETURNS timestamp AS
'DECLARE
tdat TIMESTAMP;
result RECORD;
cmd TEXT;
BEGIN
tdat := COALESCE($1, NOW());
cmd := ''SELECT '' || quote_literal(tdat) ||
''::TIMESTAMP + INTERVAL '' ||
quote_literal($2 || '' '' || $3) || '' AS x'';
FOR result IN EXECUTE cmd LOOP
return result.x;
END LOOP;
END;
'
LANGUAGE 'plpgsql' VOLATILE;
--
Oliver Elphick olly@lfix.co.uk
Isle of Wight http://www.lfix.co.uk/oliver
GPG: 1024D/A54310EA 92C8 39E7 280E 3631 3F0E 1EC0 5664 7A2F A543 10EA
========================================
"Whosoever therefore shall be ashamed of me and of my
words in this adulterous and sinful generation; of him
also shall the Son of man be ashamed, when he cometh
in the glory of his Father with the holy angels."
Mark 8:38
Thanks! Now I get it...
naeem
-----Original Message-----
From: Oliver Elphick [mailto:olly@lfix.co.uk]
Sent: Tuesday, October 26, 2004 3:05 PM
To: Naeem Bari
Cc: pgsql-general@postgresql.org
Subject: Re: [GENERAL] Newbie question about escaping in a function
On Tue, 2004-10-26 at 11:57 -0500, Naeem Bari wrote:
> I have a simple function defined thusly:
>
>
>
> CREATE OR REPLACE FUNCTION datemath(timestamp with time zone, int4,
> varchar)
>
> RETURNS timestamp AS
>
> '
>
> DECLARE
>
> tdat timestamp;
>
> rdat timestamp;
>
> BEGIN
>
> IF ($1 IS NULL) THEN
>
> TDAT := NOW();
>
> ELSE
>
> TDAT := $1;
>
> END IF;
It's neater to use the COALESCE() function, which is designed expressly
for this.
> select tdat + interval ''$2 $3'' into rdat;
In PL/pgSQL that should be "select into rdat ..."; but that won't work
in any case because you can't use passed parameters inside a string like
that.
> return rdat;
>
> END;
>
> '
>
> LANGUAGE 'plpgsql' VOLATILE;
>
>
>
> The problem is the interval part. How do I tell the bugger to use the
> second and third params as input to interval? I have tried different
> ways of escaping, from \'$2 $3\' to ''$2 $3'' and everything else in
> between, it just doesn't like it.
You have to construct a command string and use EXECUTE:
CREATE OR REPLACE FUNCTION datemath(timestamp with time zone, int4,
varchar)
RETURNS timestamp AS
'DECLARE
tdat TIMESTAMP;
result RECORD;
cmd TEXT;
BEGIN
tdat := COALESCE($1, NOW());
cmd := ''SELECT '' || quote_literal(tdat) ||
''::TIMESTAMP + INTERVAL '' ||
quote_literal($2 || '' '' || $3) || '' AS x'';
FOR result IN EXECUTE cmd LOOP
return result.x;
END LOOP;
END;
'
LANGUAGE 'plpgsql' VOLATILE;
--
Oliver Elphick olly@lfix.co.uk
Isle of Wight http://www.lfix.co.uk/oliver
GPG: 1024D/A54310EA 92C8 39E7 280E 3631 3F0E 1EC0 5664 7A2F A543 10EA
========================================
"Whosoever therefore shall be ashamed of me and of my
words in this adulterous and sinful generation; of him
also shall the Son of man be ashamed, when he cometh
in the glory of his Father with the holy angels."
Mark 8:38
Try using EXECUTE. http://www.postgresql.org/docs/7.4/static/plpgsql- statements.html#PLPGSQL-STATEMENTS-EXECUTING-DYN -tfo -- Thomas F. O'Connell Co-Founder, Information Architect Sitening, LLC http://www.sitening.com/ 110 30th Avenue North, Suite 6 Nashville, TN 37203-6320 615-260-0005 On Oct 26, 2004, at 11:57 AM, Naeem Bari wrote: > I have a simple function defined thusly: > > > > CREATE OR REPLACE FUNCTION datemath(timestamp with time zone, int4, > varchar) > > RETURNS timestamp AS > > ' > > DECLARE > > tdat timestamp; > > rdat timestamp; > > BEGIN > > IF ($1 IS NULL) THEN > > TDAT := NOW(); > > ELSE > > TDAT := $1; > > END IF; > > > > select tdat + interval ''$2 $3'' into rdat; > > return rdat; > > END; > > ' > > LANGUAGE 'plpgsql' VOLATILE; > > > > The problem is the interval part. How do I tell the bugger to use the > second and third params as input to interval? I have tried different > ways of escaping, from \’$2 $3\’ to ‘’$2 $3’’ and everything else in > between, it just doesn’t like it. > > > > Help! J > > > > Thanks, > > naeem