Обсуждение: Dynamic expression evaluation
Hello, Imagine we have the following kind of table, with two values (a and b), and a varchar (f) representing an expression. ---------------------------------- CREATE TABLE public.test ( id serial NOT NULL, a int4, b int4, f varchar(50), CONSTRAINT id PRIMARY KEY (id) ) WITHOUT OIDS; INSERT INTO public.test(a,b,f) VALUES(2,3,'a+b'); INSERT INTO public.test(a,b,f) VALUES(12,3,'a*b'); INSERT INTO public.test(a,b,f) VALUES(5,6,'a+2*b'); ---------------------------------- Is there a simple way of doing "kind of" a SELECT *, EVAL(f) FROM public.test; ... and having f evaluated as an expression, so that we get back: ------------------------------ id a b f eval ------------------------------ 1 2 3 a+b 5 2 12 3 a*b 36 3 5 6 a+2*b 17 ------------------------------ Has anyone done anything like that already? Thanks! Philippe
"Philippe Lang" <philippe.lang@attiksystem.ch> writes:
> Is there a simple way of doing "kind of" a
> SELECT *, EVAL(f) FROM public.test;
> ... and having f evaluated as an expression, so that we get back:
> ------------------------------
> id a b f eval
> ------------------------------
> 1 2 3 a+b 5
> 2 12 3 a*b 36
> 3 5 6 a+2*b 17
> ------------------------------
Not really. You can sort of approximate eval() with plpgsql's EXECUTE:
regression=# create or replace function eval(text) returns int as '
regression'# declare res record;
regression'# begin
regression'# for res in execute ''select '' || $1 || '' as result'' loop
regression'# return res.result;
regression'# end loop;
regression'# end' language plpgsql;
CREATE FUNCTION
regression=# select eval ('23+34');
eval
------
57
(1 row)
regression=#
but this has a problem with supporting more than one result type (hmm,
maybe you could fake that with 7.4's polymorphism?). And I don't see
any way at all for the function to have access to the other values in
the row, as your example presumes it would do.
regards, tom lane