Обсуждение: COUNT(DISTINCT field) OVER (PARTITION BY another_field)

Hi list,

Does someone knows why this is not a supported feature?

I was happily SQL querying when I woke up from my dreams with this message:

ERROR:  DISTINCT is not implemented for window functions
LINE 6:  COUNT(DISTINCT handle) OVER (PARTITION BY pk_pessoas) AS ha...

It could be very useful to find unique references within groups of clone records. Or there is another way to write this kind of query?

Example (reference is a column of record_data):

SELECT
 group_key,
 record_data.*,
COUNT(DISTINCT reference) OVER (PARTITION BY group_key) AS unique_references
FROM record_data
ORDER BY
 group_key;

Regards,
--
Daniel Cristian Cruz
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