Re: devide and summarize sql result (all)

<div style="font-family: Verdana;font-size: 12.0px;"><div><div>Thanks for your Answers,</div><div> </div><div>my
problemis, that there is no column with the name 'percentage'.</div><div>It's just a result of my query. So how can I
useit anyway?</div><div>Should I just store the result in a record variable and do another
query?</div><div> </div><div>Janek</div><div> <div name="quote" style="margin:10px 5px 5px 10px; padding: 10px 0 10px
10px;border-left:2px solid #C3D9E5; word-wrap: break-word; -webkit-nbsp-mode: space; -webkit-line-break:
after-white-space;"><divstyle="margin:0 0 10px 0;"><b>Gesendet:</b> Freitag, 16. August 2013 um 00:24 Uhr<br
/><b>Von:</b> bricklen<bricklen@gmail.com><br /><b>An:</b> "Janek Sendrowski" <janek12@web.de><br
/><b>Cc:</b> "pgsql-general@postgresql.org"<pgsql-general@postgresql.org><br /><b>Betreff:</b> Re: [GENERAL]
devideand summarize sql result (all)</div><div name="quoted-content"><div><div class="gmail_extra"><div
class="gmail_quote">OnThu, Aug 15, 2013 at 1:51 PM, Janek Sendrowski <span><<a href="janek12@web.de"
target="_parent">janek12@web.de</a>></span>wrote: <blockquote class="gmail_quote" style="margin: 0.0px 0.0px 0.0px
0.8ex;border-left:1.0px solid rgb(204,204,204);padding-left: 1.0ex;"><div><div style="font-family: Verdana;font-size:
12.0px;"><div>Hi,<br/>  <br /> My sql query results sth. like this:<br />  <br /> user percentage<br /> franz 78%<br />
smith98%<br /> franz 81%<br /> jason 79%</div><div>smith 89%</div><div>smith 85%</div><div>smith
99%</div><div> </div><div>NowI'd like to summarize the percentages oder every user like
this.</div><div>smith</div><div>2matches 95-100%</div><div>2 matches 85-95%</div><div>0 mathes
75-85%</div><div> </div><div>franz</div><div>0mathes
95-100%</div><div>...</div></div></div></blockquote></div></div><divclass="gmail_extra">A CASE statement should work,
ifyou are willing to hard-code the list of expressions.<br /><br /> SELECT  username,<br />         sum(case when avg
between76 and 85 then 1 else 0 end) as "76 to 85",<br />         sum(case when avg between 86 and 95 then 1 else 0 end)
as"86 to 95",<br />         sum(case when avg > 95 then 1 else 0 end) as ">95"<br /> FROM yourtable<br /> GROUP
BYusername</div><div class="gmail_extra"> </div></div></div></div></div></div></div>