Re: Getting the output of a function used in a where clause
От | PFC |
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Тема | Re: Getting the output of a function used in a where clause |
Дата | |
Msg-id | op.so1772t7th1vuj@localhost обсуждение исходный текст |
Ответ на | Getting the output of a function used in a where clause ("Bill Lawrence" <bill.lawrence@cox.net>) |
Ответы |
Re: Getting the output of a function used in a where clause
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Список | pgsql-sql |
try: SELECT zipcode, zipdist($lat1d,$lon1d,lat,long) as distance from zipcodes where distance <= $dist;”; OR you could use a gist index with a geometric datatype to get it a lot faster. On Sat, 09 Apr 2005 03:43:39 +0200, Bill Lawrence <bill.lawrence@cox.net> wrote: > HI, > > I’m a newbie so please bear with me. I have a function defined (got it > from > one of your threads… thanks Joe Conway) which calculates the distance > between 2 zip code centeroids (in lat,long). This thing works great. > However, I want to sort my results by distance without incurring the > additional burden of executing the function twice. A simplified version > of > my current SQL (written in a perl cgi) that returns a set of zip codes > within a given radius is: > > > What I want to write is something like: > > $sql = “SELECT zipcode, distance from zipcodes where distance <= $dist > order > by distance;”; > > But I don’t the magic SQL phrase to populate the distance variable using > my > nifty function. Do I need to create an output type for distance? > > Thanks in advance! > > Bill > > >
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