On 9/25/20 3:25 PM, Karsten Hilbert wrote:
> On Fri, Sep 25, 2020 at 03:19:12PM -0700, Adrian Klaver wrote:
>
>>> Sure, there's a number of solutions to my immediate problem,
>>> the fitting of which is
>>>
>>> for key in dict(DictRow):
>>>
>>> That's the best fit because my
>>>
>>> def _escape_dict(the_dict, ...):
>>>
>>> was inaptly named. It should have been (and now is)
>>>
>>> def _escape_dict_like(dict_like, ...):
>>>
>>> within which
>>>
>>> dict(dict_like)
>>>
>>> is quite the thing to do despite having to make something a
>>> duck which already nearly quacks like one is somehwat
>>> unfortunate.
>>
>> I'm pretty sure DictRow has had the same behavior for some time so:
>>
>> Are you migrating from Python 2?
>
> I did not too long ago.
So that explains the error that popped up.
>
>> Or what changed that made this show up?
>
> At the very core ? My grandpa was admitted to a hospital :-)
Sorry to hear that, it's a trial.
>
> Karsten
> --
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>
>
--
Adrian Klaver
adrian.klaver@aklaver.com