STANDBY_LOCK_TIMEOUT may not interrupt ProcWaitForSignal()?

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От Fujii Masao
Тема STANDBY_LOCK_TIMEOUT may not interrupt ProcWaitForSignal()?
Дата
Msg-id db440eee-43a0-0874-2e24-0883c1d2ce75@oss.nttdata.com
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Ответы Re: STANDBY_LOCK_TIMEOUT may not interrupt ProcWaitForSignal()?  (Fujii Masao <masao.fujii@oss.nttdata.com>)
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Hi,

When the startup process needs to wait for recovery conflict on lock,
STANDBY_LOCK_TIMEOUT is enabled to interrupt ProcWaitForSignal()
if necessary. If this timeout happens, StandbyLockTimeoutHandler() is
called and this function does nothing as follows.

     /*
      * StandbyLockTimeoutHandler() will be called if STANDBY_LOCK_TIMEOUT is exceeded.
      * This doesn't need to do anything, simply waking up is enough.
      */
     void
     StandbyLockTimeoutHandler(void)
     {
     }

But if STANDBY_LOCK_TIMEOUT happens just before entering ProcWaitForSignal(),
the timeout fails to interrupt that wait. Also a signal sent by this timeout
doesn't interrupt poll() used in ProcWaitForSignal(), on all platforms.

So I think that StandbyLockTimeoutHandler() should do SetLatch(MyLatch)
so that the timeout can interrupt ProcWaitForSignal() even in those cases.
Thought?

Regards,

-- 
Fujii Masao
Advanced Computing Technology Center
Research and Development Headquarters
NTT DATA CORPORATION



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