On Tue, 21 May 2019 21:28:07 -0700, Lev Kokotov <lev.kokotov@gmail.com>
wrote:
>Is it efficient to use Postgres as a column store by creating one
table per
>column?
>
>I would query it with something like `[...] UNION SELECT value AS <table>
>FROM <table> WHERE value = <value> UNION [...]` to build a row.
I think you mean JOIN.
You'd need more than that: Postgresql uses MVCC for concurrency, so
whenever you update any row in a table, the ordering of the rows within
the table changes. And the JOIN operation inherently is unordered - you
need to sort the result deliberately to control ordering.
To emulate a column-store, at the very least you need a way to associate
values from different "columns" that belong to the same "row" of the
virtual table. IOW, every value in every "column" needs an explicit
"row" identifier. E.g.,
col1 = { rowid, value1 }, col2 = { rowid, value2 }, ...
For performance you would need to have indexes on at least the rowid in
each of the "column" tables.
This is a bare minimum and can only work if the columns of your virtual
table and the queries against it are application controlled or
statically known. If you want to do something more flexible that will
support ad hoc table modifications, elastically sized values (strings,
bytes, arrays, JSON, XML), etc. this example is not suffice and the
implementation can get very complicated very quickly
Justin Pryzby was not joking when he said the performance could be awful
... at least as compared to a more normal row-oriented structure.
Performance of a query that involves more than a handful of "columns",
in general, will be horrible. It is up to you to decide whether some
(maybe little) increase in performance in processing *single* columns
will offset likely MASSIVE loss of performance in processing multiple
columns.
>I'm thinking since Postgres stores tables in continuous blocks of 16MB
each
>(I think that's the default page size?)
Default page size is 8 KB. You'd have to recompile to change that, and
it might break something - a whole lot of code depends on the knowing
the size of storage pages.
George