Re: Selecting all variations of job title in a list
| От | Adrian Klaver |
|---|---|
| Тема | Re: Selecting all variations of job title in a list |
| Дата | |
| Msg-id | ce79df34-8663-441d-b1c4-a1b2a78dc13b@aklaver.com обсуждение исходный текст |
| Ответ на | Re: Selecting all variations of job title in a list (Rich Shepard <rshepard@appl-ecosys.com>) |
| Ответы |
Re: Selecting all variations of job title in a list
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| Список | pgsql-general |
On 11/25/25 11:08, Rich Shepard wrote: > On Tue, 25 Nov 2025, Adrian Klaver wrote: > >> Something like?: >> >> select 'Env mgr.' ilike ANY(ARRAY['Asst Gen Mgr.', 'Env Mgr.', 'Gen >> Mgr.', 'Mgr.','Plant Mgr.']); > > Adrian, > > Hadn't thought of this. > > Your, and Ron's, answers taught me that the answer to my question is 'no, > there is no shortcut.' :-) You will need to be clearer about what you want. If it is to fetch titles with Mgr in the name then it would be simple: select * from people_table where title ilike '%mgr%'; If it is something more selective you will need to provide a more detailed example. > > Thanks, > > Rich > > -- Adrian Klaver adrian.klaver@aklaver.com
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