Re: pgbench - allow to create partitioned tables

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От Fabien COELHO
Тема Re: pgbench - allow to create partitioned tables
Дата
Msg-id alpine.DEB.2.21.1909171429440.16377@lancre
обсуждение исходный текст
Ответ на Re: pgbench - allow to create partitioned tables  (Amit Kapila <amit.kapila16@gmail.com>)
Ответы Re: pgbench - allow to create partitioned tables  (Amit Kapila <amit.kapila16@gmail.com>)
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Hello Amit,

>> One more comment:
>> +typedef enum { PART_NONE, PART_RANGE, PART_HASH, PART_UNKNOWN }
>> +  partition_method_t;
>>
>> See, if we can eliminate PART_UNKNOWN.

I'm not very happy with this one, but I wanted to differentiate "we do 
know that it is not partitioned" from "we do not know if it is 
partitioned", and I did not have a better idea.

>  I don't see much use of same.

Although it is not used afterwards, we could display the partitioning 
information differently between the two cases. This is not done because I 
did not want to add more lines on the "normal" case.

>> It is used at one place where we can set PART_NONE without much loss.
>> Having lesser invalid values makes code easier to follow.
>
> Looking more closely at this case:
> + else if (PQntuples(res) != 1)
> + {
> + /* unsure because multiple (or no) pgbench_accounts found */
> + partition_method = PART_UNKNOWN;
> + partitions = 0;
> + }
>
> Is it ever possible to have multiple pgbench_accounts considering we
> have unique index on (relname, relnamespace) for pg_class?

The issue is that it is not directly obvious which relnamespace will be 
used by the queries which rely on non schema qualified "pgbench_accounts". 
Each schema could theoretically hold a pgbench_accounts table. As this is 
pretty unlikely, I did not attempt to add complexity to resolve taking 
into account the search_path, but just skipped to unknown in this case, 
which I expect nobody would hit in normal circumstances.

Another possible and unlikely issue is that pgbench_accounts could have 
been deleted but not pgbench_branches which is used earlier to get the 
current "scale". If so, the queries will fail later on anyway.

-- 
Fabien.



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